Obtuse quadrilaateral. midpoint(-1,3) with slooe 1/2
distance 2
Answer:
1 and 3/7 hour
Step-by-step explanation:
Every hour they get 140 miles closer (100 + 40). So you divide 200 by 140 which gets you 1.42... or 1 and 3/7 of an hour.
36 miles an hour
3miles/5min to x/60min multiply top and bottom by 12 and you get 36miles/60min
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Simple just subtract and u get-74.85
