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guajiro [1.7K]
3 years ago
9

A flying disc has a radius of 3 2/3 inches. What is the approximate circumference rounded to the nearest inch?

Mathematics
2 answers:
LenaWriter [7]3 years ago
3 0

Answer:

multiply by 2

Step-by-step explanation:

tangare [24]3 years ago
3 0

Answer:

i would say multiply by 2

hope this helps

Step-by-step explanation:

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Elena went to a sporting goods store that was having a sale. She bought a tennis ball and 3 cans of tenis balls The tennis racke
Kazeer [188]

Answer: She will pay $52.68, including taxes

Step-by-step explanation: One can of tennis ball is $4 and there are no discount on it. Elena bought 3 cans, so:

can = 3 x 4 = 12

One tennis racket is $43 but it has a discount of 15%:

discount = 0.15 x 43 = 6.45

total racket = 43 - 6.45 = 36.55

Elena will have to pay:

pay = 12 + 36.55 = 48.55

She will also have to pay taxes, which are 8.5% over the price she paid:

pay + tax = 48.55 x 0.085 = 4.13

total to pay = 48.55 + 4.13 = 52.68

Buying 3 can of tennins ball and one racket, Elena paid $52.68, including taxes.

4 0
3 years ago
Hello If you are reading this you are indeed very cool and you do not deserve a BAD TIME indeed you deserve a GOOD TIME so here
bixtya [17]

Answer:

Oh if I could hug you

Step-by-step explanation:

tysm you are the best!

8 0
3 years ago
128.34 as a mixed number in simplest form
katrin2010 [14]
128.34
= 128+ 0.34
= 128+ 34/100
= 128+ (34/2) / (100/2)
= 128+ 17/50
= 128 17/50

128.34 written as a mixed number is 128 17/50~
7 0
2 years ago
Witch expression is the factorization of x2+10x+21
Alenkasestr [34]

Answer:

x^2 +x(7+3) +21

x^2 +7x + 3x +21

x(x+7) +3(x+7)

(x+7) (x+3)

6 0
3 years ago
What degree of rotation is represented on this matrix
Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, -90^{\circ}

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}

Given the matrix: \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

Now, equate the given matrix with standard matrix we have;

\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix} =  \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

On comparing we get;

\cos \theta = 0       and -\sin \theta =1  

As,we know:

  • \cos \theta = \cos(-\theta)
  • \sin(-\theta) = -\sin \theta

\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})

we get;

\theta = -90^{\circ}

and

\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})

we get;

\theta = -90^{\circ}

Therefore, the degree of rotation is, -90^{\circ}

7 0
3 years ago
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