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3 years ago

8

Glenn Andrews recently bought a new motorbike for $3,950. If he had to pay 6 percent sales tax on the

1 answer:

GalinKa [24]3 years ago

4 0

The total amount of money he had to pay for the bike is $3,954.02 because 6 percent of 7 is 4.2

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State the horizontal asymptote of the rational function. For full credit, explain the reasoning you used to find the horizontal

Rzqust [24]

So here are the rules of horizontal asymptotes:

Degree of Numerator > Degree of Denominator: No horizontal asymptote
Degree of Numerator = Degree of Denominator: $y=\frac{\textsf{leading coefficient of numerator}}{\textsf{leading coefficient of denominator}}$
Degree of Numerator < Degree of Denominator: y = 0

Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>

5 0

3 years ago

What is the quotient of <br><br> 5<br><br> 43 ÷ 25<br><br> 86 = _____

Softa [21]

1. What is the value of y in the equation 4 + y = –3? y = -3 – 4 y = -7

3 0

3 years ago

ANSWER AS MANY AS POSSIBLE! I WILL MARK BRAINLIEST!!!

kodGreya [7K]

Answer:

88c = -300

105c = 81300

105b = 294

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y

castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.
$P(A \cap B)$ is the probability of both A and B happening.
P(A) is the probability of A happening.

In this problem:

Event A: Fail the test.
Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

46% of 37%(are fit).
100% of 63%(not fit).

Hence:

$P(A) = 0.46(0.37) + 0.63 = 0.8002$

The probability of both failing the test and being unfit is:

$P(A \cap B) = 0.63$

Hence, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873$

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0

2 years ago

(Please give the step to step procedure) Due to short supply in the market a shopkeeper raises the price of a cycle by 5% above

Tatiana [17]

Answer:

4000

Step-by-step explanation:

let the marked price of the cycle be x

then x · (100% + 5% + 12%) = 4680

x = $\frac{4680}{1.17}$ = 4000

6 0

3 years ago

Read 2 more answers