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Lerok [7]
2 years ago
8

Can someone please give me the answer I will mark u brilliant as soon as it pops up.

Mathematics
1 answer:
adelina 88 [10]2 years ago
7 0

9514 1404 393

Answer:

  (a)  26 units

Step-by-step explanation:

The left-side vertical line extends from y = -3 to y = +3, so is 3-(-3) = 6 units long.

The bottom side horizontal line extends from x = -5 to x = 2, so is 2 -(-5) - 7 units long.

The sum of these two sides is 6 + 7 = 13 units. These two sides make up half of the perimeter, which is the total length of all four sides.

The perimeter is 2 × 13 units = 26 units.

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Which relation is a function?
olya-2409 [2.1K]

Answer:

1,2,4,8,16,32,36,40,48

6 0
3 years ago
Last repeats, i cant find answer. pls help, am i use wrong way ? ​
muminat

Answer:

question is not clear pls resend

8 0
2 years ago
Read 2 more answers
Triangle RST is diated to form triangle R'S'T with the scale factor of 3.5. If RT=8 what is the length of R'T
shepuryov [24]

Answer:

R'T = 28

Step-by-step explanation:

Dilation is one of the methods used in transformation. It is a process in which the size of a given object or shape is either increased or decreased by a scale factor.

In the given question, the length of RT was increased by the scale factor, so that;

R'T = RT x scale factor

      = 8 x 3.5

      = 28

R'T = 28

Therefore, the length of R'T is equal to 28.

3 0
2 years ago
X+3<8 and 3(x+4)-11<10
kondaur [170]

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

4 0
3 years ago
How do I do question 9? Please give answer thank you
kvasek [131]
<h3>Given</h3>
  • a cone of height 0.4 m and diameter 0.3 m
  • filling at the rate 0.004 m³/s
  • fill height of 0.2 m at the time of interest
<h3>Find</h3>
  • the rate of change of fill height at the time of interest
<h3>Solution</h3>

The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of

... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²

This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.

... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s

Dividing by the coefficient of dh/dt, we get

... dh/dt = 0.004·16/(0.09π) m/s

... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s

_____

You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)

Note that the cone dimensions mean the radius is 3/8 of the height.

V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³

dV/dt = 9π/64·h²·dh/dt

.004 = 9π/64·0.2²·dh/dt . . . substitute the given values

dh/dt = .004·64/(.04·9·π) = 32/(45π)

7 0
3 years ago
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