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3 years ago

9

What is the composition of transformations mapping ABC to A'B'C"? The first transformation is The second transformation is AABC

is AA'B"C".

1 answer:

spin [16.1K]3 years ago

3 0

Answer:

The first Transition is a reflection over the line M

The second transition is a 180 degree rotation.

Step-by-step explanation:

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HELP I REALLY NEED HELP ON THIS !

Serjik [45]

4) your last two choices.

5) your second choice.

6) your third choice.

7) your first choice.

8) your third choice.

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3 years ago

Parallelogram ABCD has vertices at A(2,-3), B(8,-6), Cl14,-3), and D(8,0)

OlgaM077 [116]

Answer:

The correct option is C.

Step-by-step explanation:

The vertices of ABCD are A(2,-3), B(8,-6), C(14,-3), and D(8,0).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of sides are

$AB=\sqrt{(8-2)^2+(-6+3)^2}=\sqrt{36+9}=\sqrt{45}$

$BC=\sqrt{(14-8)^2+(-3+6)^2}=\sqrt{36+9}=\sqrt{45}$

$CD=\sqrt{(8-14)^2+(0-3)^2}=\sqrt{36+9}=\sqrt{45}$

$AD=\sqrt{(8-2)^2+(0+3)^2}=\sqrt{36+9}=\sqrt{45}$

Since length of all sides are equation therefore the given parallelogram cannot be a rectangle.

Slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of AB is

$m_1=\frac{-6-(-3)}{8-2}=\frac{-3}{6}=\frac{-1}{2}$

Slope of BC is

$m_2=\frac{-3-(-6)}{14-8}=\frac{3}{6}=\frac{1}{2}$

Since the slopes of two consecutive sides are not opposite reciprocals, therefore the given parallelogram is a rhombus. Option C is correct.

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3 years ago

What is the area of a sector with a central angle of 8 π/11 radians and a radius of 7.2 ft? use 3.14 for π and round your final

coldgirl [10]

Answer:

$59.19 ft^2$

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=7.2\ ft$

$\pi =3.14$

substitute

$A=(3.14)(7.2)^{2}$

$A=162.78\ ft^2$

step 2

we know that

The area of a circle subtends a central angle of 2π radians

so

using proportion

Find out the area of a sector with a central angle of 8 π/11 radians

$\frac{162.78}{2\pi }\frac{ft^2}{rad} =\frac{x}{(8\pi/11)}\frac{ft^2}{rad} \\\\x=162.78(8/11)/2\\\\x=59.19\ ft^2$

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4 years ago

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