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3 years ago

9

What is the composition of transformations mapping ABC to A'B'C"? The first transformation is The second transformation is AABC

is AA'B"C".

1 answer:

spin [16.1K]3 years ago

3 0

Answer:

The first Transition is a reflection over the line M

The second transition is a 180 degree rotation.

Step-by-step explanation:

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Compare the rate at which each of the three students read.

laiz [17]

Answer:

here is the ANSWER-Connie : 1min = 200 words

Felicia : 1min = 260 words

Stew : 1 min = 265 words (8min = 2120 words, and 7min = 1855 words, so you minus 2120 - 1855 = 265 words)

STEW is the ANSWER

6 0

3 years ago

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Simplify the following expression: (52)^8

liberstina [14]

Answer: brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6https://brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6https://brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6

4 0

2 years ago

Read 2 more answers

Solve the following quadratic equation for its exact value by using the square root principle.

Korvikt [17]

Idk what the hell all that is but x = 1.802775637731995

4x^2 - 13 = 0

4x^2 = 13

13/4=3.25

x^2 = 3.25

x = ~1.8

5 0

3 years ago

b)suppose only 1 in every 1,000 stars in the observable universe has a planetary system. how many planetary system are there? Fi

rosijanka [135]

Answer:

Please read below :)

Step-by-step explanation:

so you have 1 in a 1000, or 1/1000. But you're missing a part of the answer. If you post the whole answer I can give you the correct answer :)

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3 years ago