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3 years ago

How can you tell there is no solution of a system of equations by looking at the equations or the graph? Explain.

1 answer:

5 0

Each shows two lines that make up a system of equations. If the graphs of the equations intersect, then there is one solution that is true for both equations. If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

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How to solve logarithmic equations as such

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$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

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3 years ago

What is the area of a piece of garden plot 5 yards 2 feet long by 6 yards 1 foot wide? Give your answer in square feet. A. 323 s

Blababa [14]

change yrds to ft

5yds = 5*3 = 15 ft

5yds 2 ft = 15ft + 2ft = 17 ft

6yds = 6 * 3 = 18 ft

6 yds 1 ft = 18 + 1

19 ft

A = l * w

A = 17* 19

A = 323 ft^2

Choice A

6 0

3 years ago

How can you tell there is no solution of a system of equations by looking at the equations or the graph? Explain.​

How can you tell there is no solution of a system of equations by looking at the equations or the graph? Explain.