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creativ13 [48]
3 years ago
9

Find the value for x. 5x - 12 3x + 30 48

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0
Is this the way the question is laid out? is there an equal sign anywhere
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Help i dont feel like doing the math
BARSIC [14]

Answer:

A

Step-by-step explanation:

First, we should put this equation in slope-intercept form by isolating y.

Thus, we have:

2x-\frac{4}{3}y=4\\ -\frac{4}{3}y=4-2x\\ y=\frac{3}{2}x-3

The slope-intercept equation shows that the y-intercept is -3 and the slope is 3/2.

Only answer A meets these requirements.

8 0
1 year ago
Jennifer is saving money to buy a bike. The bike costs $326. She has $131 saved, and each week she adds $15 to her savings. How
motikmotik

Answer: It should take her 13 weeks.

Step-by-step explanation:

If the bike costs $326 and she already has $131, we can subtract 131 from 326. 326-131=195. Now we know that Jennifer needs $195 dollars. Next, since she adds $15 each week, divide 195 by 15. 195/15= 13. It should take Jennifer 13 weeks so save up for her bike.

8 0
3 years ago
Write an equation that shows the relatiinship of 40%, x, and 35​
Ganezh [65]
One answer could be x=40% of 35
8 0
3 years ago
Josiah earns $8.00 per hour at his job.
Wittaler [7]

Answer:

15 hours

so, 8 x y = 120

Step-by-step explanation:

8\sqrt{120}  = 15

6 0
3 years ago
A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%
Mamont248 [21]

Answer:

a. A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\

b. \frac{dA}{dt}= -11.25 \frac{mg}{h}

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0
3 years ago
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