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melomori [17]
3 years ago
14

How do you multiply fractions with a whole number

Mathematics
2 answers:
Allisa [31]3 years ago
5 0
You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.

Sergio [31]3 years ago
3 0
When multiplying fractions and whole numbers, you either turn the fraction into a decimal, or the whole number into a fraction.

For example, the solution for 2/5(8) can be found by turning 2/5 into a decimal (0.4) and multiplying that by 8, or by turning 8 into a fraction (8/1) and multiplying those together.
You will get 3.2 and 16/5. 16/5 can be simplified to be 3 1/5, or 3.2. As you can see, either method works and will give you the same answer.
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es 12.5 the intercepts and domain, and perform the symmetry test on each of the following ellipses: 6x2 + 25y2 = 400 2 + 472 = 4
Anastaziya [24]

Answer:

the question is cutoff. please rewrite the question. please write exponents as 6x^2.

6 0
3 years ago
Consider the function, f(x) = 3x - 3. Determine the asymptote for the function f(x).
Natali [406]

Answer:

Y= 1

Step-by-step explanation:

Given the expression f(x) = 3x - 3.

To solve for the asymptote y

Firstly we need to solve for x

3x-3=0

3x=3

x= 3/3

x=1

Hence the asymptote of the function y=1

5 0
3 years ago
I'm completely lost
Vladimir [108]
Let x be the number of racing bikes, and let y be the number of mountain bikes.
1) 140x + 110y = 26150
2) 180x + 120y = 31800
Solve for one of the variables and plug that in to the other equation:
From equation 1: 140x = 26150 - 110y
x = (26150-110y)/140
Plug this into equation 2:
180((26150-110y)/140) = 31800
Solve for y, and find that y = 85 (the number of mountain bikes).
Plug that y into either equation to find x:
140x + 110(85) = 26150
x = 120 (the number of racing bikes).
So the answer is: 120 racing bikes and 85 mountain bikes.
4 0
3 years ago
which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2
Wewaii [24]

You know that 100=10^2.

Use the property (ab)^2=a^2\cdot b^2 to state that

100n^2=10^2\cdot n^2=(10n)^2.

Then the expression 100n^2-1 is equivalent to

(10n)^2-1=(10n)^2-1^2.

Answer: correct choice is A.

5 0
3 years ago
Read 2 more answers
HELP THIS IS IMPORTANT!!! The range of the following relation R {(3.-5), (1, 2), (-1,-4),(-1, 2)} is (1 point) Oa ng 1-1.1.3) Ob
garri49 [273]

Answer:

The range is -5,2,-4,

Step-by-step explanation:

hope that helps

4 0
3 years ago
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