All categories

3 years ago

How do you multiply fractions with a whole number

2 answers:

5 0

You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.

Sergio [31]3 years ago

3 0

When multiplying fractions and whole numbers, you either turn the fraction into a decimal, or the whole number into a fraction.

For example, the solution for 2/5(8) can be found by turning 2/5 into a decimal (0.4) and multiplying that by 8, or by turning 8 into a fraction (8/1) and multiplying those together.
You will get 3.2 and 16/5. 16/5 can be simplified to be 3 1/5, or 3.2. As you can see, either method works and will give you the same answer.

You might be interested in

Solve this equation by using the look inside method to rewrite the problem <br><br> -81 = 3(5 - 4r)

TEA [102]

－81＝3(5－4r)
27＝－(5－4r)
27＝－5＋4r
－4r＝－5－27
－4r＝－32
r＝8

Hope my answer helped u :)

4 0

2 years ago

Solve for x.

olga nikolaevna [1]

Answer:

$\boxed{x=5},x=-9$

Step-by-step explanation:

To rid the denominators, multiply both sides by $(x-3)(x+1)$ .

We get:

$6(x+1)-12(x-3)=(x-3)(x+1)$

Simplifying, we have:

$6x+6-12x+36=x^2-3x+x-3,\\-6x+42=x^2-2x-3,\\x^2+4x-45=0$

Solving, we get:

$x^2+4x-45=0,\\(x-5)(x+9)=0,\\x=5,x=-9$

Therefore, the solution with the greatest value is $x=\boxed{5}$

8 0

2 years ago

You are shopping for a new pair of jeans and

kirill [66]

Answer:

7% percent off of $33.00 would be $30.69 cents

Hope helps

7 0

2 years ago

Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).

Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

$m_1=\frac{7-0}{3-0}=\frac{7}{3}$

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)$

The slope of the line joining E(7,0), and F(3,7). is:

$m_1=\frac{7-0}{3-7}=-\frac{7}{4}$

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)$