![\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bn%5E2-10n%2B24%7D%7Bn%5E2-13n%2B42%7D-%5Cfrac%7B9%7D%7Bn-7%7D%3D%5Cfrac%7B%28n-6%29%28n-4%29%7D%7B%28n-6%29%28n-7%29%7D-%5Cfrac%7B9%7D%7Bn-7%7D%5C%5C%5C%5C%3D%5Cfrac%7Bn-4%7D%7Bn-7%7D-%5Cfrac%7B9%7D%7Bn-7%7D%3D%5Cfrac%7Bn-4-9%7D%7Bn-7%7D%5C%5C%5C%5C%3D%5Cfrac%7Bn-13%7D%7Bn-7%7D)
The last choice is appropriate.
Answer:5
Step-by-step explanation:
2+2=4+1=5
For this case we have a function of the form:
![y = A * (b) ^ x](https://tex.z-dn.net/?f=%20y%20%3D%20A%20%2A%20%28b%29%20%5E%20x%20%20)
Where,
A: initial population of bacteria
b: growth rate
x: number of hours
Since the diameter is double every hour, then:
![b = 2](https://tex.z-dn.net/?f=%20b%20%3D%202%20%20)
We must now look for the value of A.
To do this, we evaluate an ordered pair of the graph:
For (1, 2):
![2 = A * (2) ^ 1](https://tex.z-dn.net/?f=%202%20%3D%20A%20%2A%20%282%29%20%5E%201%20%20)
Clearing A we have:
![2 = A * 2](https://tex.z-dn.net/?f=%202%20%3D%20A%20%2A%202%20%20)
![A = \frac{2}{2}\\A = 1](https://tex.z-dn.net/?f=%20A%20%3D%20%5Cfrac%7B2%7D%7B2%7D%5C%5CA%20%3D%201%20%20%20)
Then, the function is given by:
![y = 1 * (2) ^ x](https://tex.z-dn.net/?f=%20y%20%3D%201%20%2A%20%282%29%20%5E%20x%20%20)
For after 9 hours we have:
![y = 1 * (2) ^ 9\\y = 512](https://tex.z-dn.net/?f=%20y%20%3D%201%20%2A%20%282%29%20%5E%209%5C%5Cy%20%3D%20512%20%20)
Answer:
the diameter of the bacteria after 9 hours is:
![y = 512](https://tex.z-dn.net/?f=%20y%20%3D%20512%20)
I think it may be a polynomial of 11 terms (degree = 11)
Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.
Because we know 3 and -1 (multiplicity 2) are both roots, the last root
is such that we can write
![x^4-4x^3-2x^2+12x+9=(x-3)(x+1)^2(x-r)](https://tex.z-dn.net/?f=x%5E4-4x%5E3-2x%5E2%2B12x%2B9%3D%28x-3%29%28x%2B1%29%5E2%28x-r%29)
There are a few ways we can go about finding
, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be
.
Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have
![3r=9\implies r=3](https://tex.z-dn.net/?f=3r%3D9%5Cimplies%20r%3D3)
so the missing root is 3.
Other things we could have tried that spring to mind:
- three rounds of division, dividing the quartic polynomial by
, then by
twice, and noting that the remainder upon each division should be 0
- rational root theorem