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viva [34]
2 years ago
13

The original price of a dress is $39.99. Julie buys the dress when it is on sale for 10% off its original price. Two weeks later

, Mindy buys the same
dress when it is now on sale for 20% off its original price.
How much more money did Julie spend than Mindy on the dress?
$ [blank]
Enter your answer as a number. If it is a decimal, round it to the nearest whole number, like this: 42

Mathematics
1 answer:
devlian [24]2 years ago
7 0

Answer:

68b

Step-by-step explanation:

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Answer:

Origin symmetry?

Step-by-step explanation:

I believe it's origin, simply because it isn't symmetric according to either the x or y axis, but I'm not 100% sure

3 0
3 years ago
Laura made 45 hats. Laura made 5 times as many hats as Carlos, Let h be the number of hats that Carlos made.
Anestetic [448]

45 = 5h. To find h, divide each side by 5.

9 = h. To ensure we have the correct answer, plug 9 into our original equation.

45 = 5(9)

45 = 45

Carlos made 9 hats.

8 0
3 years ago
What is the answer for 6.95X12
ch4aika [34]

The answer is...........

83.4

6 0
3 years ago
Read 2 more answers
For the cost function c equals 0.1 q squared plus 2.1 q plus 8​, how fast does c change with respect to q when q equals 11​? Det
Soloha48 [4]

Answer:

Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is  9.95%

Step-by-step explanation:

Cost function is given as,  c=0.1\:q^{2}+2.1\:q+8

Given that c changes with respect to q that is, \dfrac{dc}{dq}. So differentiating given function,  

\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)

Applying sum rule of derivative,

\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)

Applying power rule and constant rule of derivative,

\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0

\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1

\dfrac{dc}{dt}=0.2\left(q\right)+2.1

Substituting the value of q=11,

\dfrac{dc}{dt}=0.2\left(11\right)+21.

\dfrac{dc}{dt}=2.2+2.1

\dfrac{dc}{dt}=4.3

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,  

Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100

Rewriting in terms of cost C,

Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100

Calculating value of C\left(q \right)

C\left(q\right)=0.1\:q^{2}+2.1\:q+8

Substituting the value of q=11,

C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8

C\left(q\right)=0.1\left(121\right)+23.1+8

C\left(q\right)=12.1+23.1+8

C\left(q\right)=43.2

Now using the formula for percentage,  

Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100

Percentage\:rate\:of\:change=0.0995\times 100

Percentage\:rate\:of\:change=9.95%

Percentage rate of change of c with respect to q is 9.95%

7 0
2 years ago
Please Answer Quick! And A Explanation Would Be Nice Too! 40 points <3
scZoUnD [109]

Answer:

Part A:

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Part B:

The line would fit at the coordinates: (5,0) (15.5) (24,10) (30,13) (35,15) (45,20) (55,25) (60,27)

4 0
3 years ago
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