Can someone help me with this it’s for science and it’s due tomorrow

Mathematics

1 answer:

8_murik_8 [283]3 years ago

6 0

Answer:

Hoping someone else can answer with more confidence, but here's what I have:

on the left hand side:

upper is partial/penumbral lunar eclipse

lower is total solar eclipse

on the right hand side:

on the top: it's impossible for the moon to be behind the sun, so I'm not sure what they want there

middle is total solar eclipse

bottom is partial/penumbral lunar eclipse

Hope I helped at least a little

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Y= 4x-9 and y=x-3 Also using transitive property

Andreyy89

Y = 4x - 9 and y = x-3 so the two right sides (4x-9 and x-3) must be equal

4x-9 = x-3

Let's solve for x

4x-9 = x-3
4x-9+9 = x-3+9 ... add 9 to both sides
4x = x+6
4x-x = x+6-x ... subtract x from both sides
3x = 6
3x/3 = 6/3 ... divide both sides by 3
x = 2

If x = 2, then y is...
y = 4*x - 9 = 4*2-9 = 8-9 = -1
which can also be found by
y = x-3 = 2-3 = -1

So overall x = 2 and y = -1

We have the ordered pair (x,y) = (2,-1)

4 0

3 years ago

Find the sum of the first 20 terms of the arithmetic sequence 4, -4, -12, -20

Vsevolod [243]

Answer:

The sum of the first 20 terms is -1440.

Step-by-step explanation:

We want to find the sum of the first 20 terms of the arithmetic sequence:

4, -4, -12, -20...

The sum of an arithmetic sequence is given by:

$\displaystyle S=\frac{k}{2}(a+x_k)$

Where k is the number of terms, a is the initial term, and x_k is the last term.

Since we want to find the sum of the first 20 terms, k = 20.

Our initial term a is 4.

Our last term is also the 20th term as we want the sum of the first 20 terms.

To find the 20th term, we can write an explicit formula for our sequence. The explicit formula for an arithmetic sequence is given by:

$x_n=a+d(n-1)$

Where a is the initial term, d is the common difference, and n is the nth term.

Our initial term is 4. From the sequence, we can see that our common difference is -8 since each subsequent term is eight less than the previous term. Therefore:

$x_n=4-8(n-1)$