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Lostsunrise [7]
3 years ago
13

Can someone help me with this it’s for science and it’s due tomorrow

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

Hoping someone else can answer with more confidence, but here's what I have:

on the left hand side:

upper is partial/penumbral lunar eclipse

lower is total solar eclipse

on the right hand side:

on the top: it's impossible for the moon to be behind the sun, so I'm not sure what they want there

middle is total solar eclipse

bottom is partial/penumbral lunar eclipse

Hope I helped at least a little

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Volume of a cylinder with a radius of 13 in and height of 30 in
Elodia [21]

Answer:

V≈15927.87 in³

Step-by-step explanation:

The volume of a cylinder is found by multiplying the area of its top or base by its height and is defined as: V = π*r²*· h

3 0
3 years ago
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Given that<br> 5x:9=7:3<br> Calculate the value of <br> x
morpeh [17]

Answer:

  • x = 4.2

Step-by-step explanation:

<h3>Given  </h3>
  • 5x:9=7:3
<h3>To find</h3>
  • The value of  x
<h3>Solution</h3>
  • 5x:9=7:3
  • 5x = 7*9/3
  • 5x = 7*3
  • 5x = 21
  • x = 21/5
  • x = 4.2
7 0
3 years ago
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Graph the inequality below on the number line.<br> a&gt;4
aev [14]

Answer:

Open dot on 4 with arrow going to the right.

Step-by-step explanation:

4 is open because it is not part of the set.

6 0
3 years ago
NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
Read 2 more answers
Giving 25 points for whoever answers it with a complete explanation .. ASAP
MAXImum [283]
No, it is not a function.
Since all the lines have been drawn in the grid line do not have any connection between them even a point in common.
I hope this has been useful for you.
8 0
3 years ago
Read 2 more answers
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