Using the Pythagorean theorem:
Length of wire = sqrt(34^2 + 8^2)
Length of wire = sqrt(1156 +64)
Length of wire = sqrt(1220)
Length of wire = 34.9285 feet
There are 2 wires:
34.9285 x 2 = 69.857 feet
Round off as needed.
Answer:
Step-by-step explanation:
(X+4) (x^2 +1)
Answer:
Step-by-step explanation:
256
Answer: The volume of the stone is 576 cubic inches
Step-by-step explanation: The dimensions of the tank are given in feet and inches, hence we shall use the lower of the unit of measurement that is, inches. Note that 1 foot equals 12 inches, so the length is 2 feet times 12, which equals 24 inches. Also the width is 1 foot times 12 which equals 12 inches. Then the tank is filled with water up to a depth of 8 inches , so the volume of water in the tank can be calculated as follows;
Volume = L x B x H
Where Length = 24, Width = 12 and Height = 8
Volume = 24 x 12 x 8
Volume = 2304
At 2304 cubic inches, a stone is placed in the water tank and the water level rises by 2 inches which implies that the depth is now 10 inches. With the addition of the stone, the dimensions are now shown as;
Length = 24, Width = 12, and Height = 10
Volume = L x W x H
Volume = 24 x 12 x 10
Volume = 2880
With the rise in volume of water in the tank, the difference (which is the volume of the stone) now is Volume with stone minus volume without stone, that is
Volume of stone = 2880 - 2304
Volume of stone = 576
Therefore the volume of the stone is 576 cubic inches
Answer:
a) C. No, a carton can have a puncture and a smashed corner.
b) The probability that a carton has a puncture or a smashed corner is P(X ∪ Y) = 0.104.
Step-by-step explanation:
To be mutually exclusive, the probability of the two events happening at the same time should be 0. But the probability that a carton has a puncture and has a smashed corner is 0.004 and not 0.
Then, we can conclude the events "selecting a carton with a puncture" and "selecting a carton with a smashed corner" are not mutually exclusive.
The answer is "C. No, a carton can have a puncture and a smashed corner."
We can calculate the probability that the carton has a puncture <em>or </em>has a smashed comer simply by adding the probability of each event:
P(X ∪ Y): probability that a carton has a puncture or a smashed corner.
