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3 years ago

HELP PLEASE :/ math is not my bff

Mathematics

1 answer:

gtnhenbr [62]3 years ago

7 0

1. None of the answer choices are correct, because the length that were to go with those numbers don't fit. The answer is D.

2. One coffee cost $4 and a latte would cost $2.50, because the other prices for a cup of coffee would exceed the price of the total of two coffees plus one latte and three coffees plus two lattes. The answer is A: $4.00.

3. This one has to be A, because you're finding how many nickels and dimes there are together if there are 24 coins. A nickel is 5 cents each and a dime is 10 cents each. The total of them combined is $1.85. The answer is A.

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A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is <u>55%</u> when weight limit is 33 pounds.

The percentage is <u>190%</u> when weight limit is 114 pounds.

The 95% of the limit weighs <u>57</u> pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is <u>55%</u> when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is <u>190%</u> when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs <u>57</u> pounds.

4 0

4 years ago

Find a rational number between 8 and 9

otez555 [7]

<h2>⟰ ANSWER ⟰</h2>

<h2> HOPE IT HELPS U!!!!(:</h2>

4 0

3 years ago

(1.8x10^5)divided by(3x10^6) in standard form?

Softa [21]

Answer:

0.06

Step-by-step explanation:

Given data:

$1.8(10^{5})$ divided by 3× $10^{6}$

Now,

$\frac{(1.8)10^{5} }{3(10^{6}) } \\=0.6(10^{5-6} )\\=0.6(10^{-1} )\\=0.06$

Answer will be 0.06

5 0

3 years ago

I need help with geometry:

nikklg [1K]

Answer:

x = 5

Step-by-step explanation:

6/18 = x/(20-x)

1/3 = x/(20-x) Multiply both sides by 20-x

(20-x)/3 = x Multiply both sides by 3

20-x = 3x Add x in both sides

20 = 4x Divide both sides by 4

5 = x

3 0

3 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

4 years ago