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2 years ago

Can you identify a parallel or perpendicular equation and type the correct code?

Mathematics

1 answer:

AlladinOne [14]2 years ago

3 0

Answer:

The equation of the line that is parallel to is and the equation of the line that is perpendicular to is .

Let be a line whose equation is:

(1)

Whose explicit form is:

(2)

Where:

- Independent variable.

- Dependent variable.

The slope and x-intercept of the line are and , respectively.

There are two facts:

A line is parallel to other line when the former has the same slope of the latter.

A line is perpendicular to other line when the former has a slope described the following form (), where is the slope of the former.

Then, the equation of the line that is parallel to is and the equation of the line that is perpendicular to is .

To learn more on lines, we kindly invite to check this verified question: brainly.com/question/2696693

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Scores on an exam follow an approximately normal distribution with a mean of 76. 4 and a standard deviation of 6. 1 points. What

crimeas [40]

If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.

A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;

Z = x - μ / σ

In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.

The p-value can be used to determine the z-score with the help of a standard table.

As we have to find the minimum score to be in the top 2%, p-value = 0.02

The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054

Therefore,

2.054 = x - 76.4 ÷ 6.1

2.054 × 6.1 = x - 76.4

12.529 = x - 76.4

12.529 + 76.4 = x

x = 88.929

Hence 88.929 is calculated to be the lowest score required to be in the top 2%.

To learn more about normal distribution, click here:

brainly.com/question/4079902

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5 0

1 year ago

Please help!

loris [4]

m∠B = 33° is the answer.

<u>Step-by-step explanation:</u>

If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.

In any triangle, sum of the measure of the angles add up to 180°.

∠A+ ∠B+ ∠C = 180°

∠A ≅ ∠M

∠B ≅ ∠O

∠C ≅ ∠P

So we can add as,

∠A + ∠B+ ∠P = 180°

45° + ∠B + 102° = 180°

∠B + 147° = 180°

∠B = 180° - 147° = 33°

8 0

3 years ago

Circle towns limit form a perfectly circular shape that has a population of 20000 in the population density of 480 people per sq

Alex

Answer:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

Step-by-step explanation:

For this case we know the population size $P = 20000$ and we also know the population density $D = 480 \frac{people}{km^2}$

We can assume that the area is a circle. We also know that the formula for the population density is given by:

$D= \frac{P}{A}$

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

$A = \pi X^2$

With X the radius of the circle

And then the populationd density become:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

6 0

3 years ago

Find the distance labeled x in the diagram.

zheka24 [161]

Answer: B

Step-by-step explanation:????

Troll

6 0

3 years ago

An angle of 34°. If the arc is 162 feet tall, how far away is the bus? Round to the nearest tenth.

marta [7]

Answer:

the answer is 134 hope this helps.

8 0

3 years ago