If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
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m∠B = 33° is the answer.
<u>Step-by-step explanation:</u>
If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.
In any triangle, sum of the measure of the angles add up to 180°.
∠A+ ∠B+ ∠C = 180°
∠A ≅ ∠M
∠B ≅ ∠O
∠C ≅ ∠P
So we can add as,
∠A + ∠B+ ∠P = 180°
45° + ∠B + 102° = 180°
∠B + 147° = 180°
∠B = 180° - 147° = 33°
Answer:

And solving for the radius we got:

And replacing the data given we got:

And this value converted to meters is 
Step-by-step explanation:
For this case we know the population size
and we also know the population density 
We can assume that the area is a circle. We also know that the formula for the population density is given by:

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

With X the radius of the circle
And then the populationd density become:

And solving for the radius we got:

And replacing the data given we got:

And this value converted to meters is 
Answer: B
Step-by-step explanation:????
Troll
Answer:
the answer is 134 hope this helps.