Question

Plz help for exam!!! Solve for x and y.

Answer 1

Answer:

A x-198,y-99$\sqrt{3}$

Step-by-step explanation:

since sin p/h you can say

perpendicular is 99

and hypotenuse is x

sin 30=99/x

x=198

and cos is b/h

base is y

and hypotenuse is x

cos 30=y/198

y-99$\sqrt{3}$