3 years ago

Plz help for exam!!! Solve for x and y.

Mathematics

1 answer:

ad-work [718]3 years ago

6 0

Answer:

A x-198,y-99 $\sqrt{3}$

Step-by-step explanation:

since sin p/h you can say

perpendicular is 99

and hypotenuse is x

sin 30=99/x

x=198

and cos is b/h

base is y

and hypotenuse is x

cos 30=y/198

y-99 $\sqrt{3}$

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