If you multiply 6 * 5 you get 30. 30 * 103 = 3,090
There are 2 zeros in the product of (6x5)x103
x= -0.25 and 1.25
x = -0.5 and 1.5
x = 0 and 1
x = -0.375 and 1.625
Step-by-step explanation:
Given equation of the curve is

(i)
First equation 
Here y = 0
In x-axis the value of y = 0
The graph cuts the x-axis at(-0.25,0) and (1.25,0)
So, x= -0.25 and 1.25
(ii)

here y = 2
The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)
So, x = -0.5 and 1.5
Given equation of the curve is

(i)


Here y = -1
The line y = -1 cuts the curve at (0,-1) and (1,-1)
So x = 0 and 1
(ii)

Here y = x+1
The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).
So x = -0.375 and 1.625
Answer:
Step-by-step explanation: My variables are
d=big number q=small number
My equations are 6=3q2d+3=qI
will solve for q in first equation 6/3 = 3q/32=q
Now I will pluck back in to get d2d+3=(2) -3 -32d=-12d/2=-½d=-1/4 So the solution is(-1/4, .2)
Factor out the largest perfect square of 32.
( in this example we factored out 16 )
Rewrite
____
/16⋅2
as the product of two radicals.
The square root of 16 is 4.
Divide numerator and denominator by 4.
No I do not think that 12/60 and 16/40 are equivalent because onec you reduce both of the fractions it does not equal.