At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
<h3>How to state hypothesis conclusion?</h3>
We are given;
Sample size; n = 78
population standard deviation σ = 37
Sample Mean; x' = 280
Population mean; μ = 287
The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;
Null hypothesis; H₀: μ > 280
Alternative hypothesis; Hₐ: μ < 280
This is a one tail test with significance level of α = 0.13
From online tables, the critical value at α = 0.13 is z(c) = -1.13
b) Formula for the test statistic is;
z = (x- μ)/(σ/√n)
z = ((280 - 287) *√78 )/37
z = -1.67
c) From online p-value from z-score calculator, we have;
P[ z > 280 ] = 0.048
d) The value for z = -1.67 is smaller than the critical value mentioned in problem statement z(c) = - 1.13 , the z(s) is in the rejection zone. Therefore we reject H₀
e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
Read more about Hypothesis Conclusion at; brainly.com/question/15980493
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N-10+9n-3
n+9n=10n
10-3=7
so the answer is....
-13+10n
Answer: c
Step-by-step explanation:
ANSWER: 12/20 or 3/5
4/5 of girls have brown hair
3/4 have long hair
Hello there,
The answer will be <u>1</u><u>5</u><u> </u><u>students.</u>
<h3>Step-by-step explanation:-</h3>
We will solve the equation as follows:-
First add the total of the students in band and chorus -
→ 70 + 95 = 165
Then subtract the previously got number with given number of chorus students:-
→ 165 - 150 = 15
So, there are <u>15 students</u> who are there in both band and chorus.
✍️ <em>By </em><em>Benjemin</em> ☺️
