The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
<h3>What dimensions would guarantee that the garden has the greatest possible area?</h3>
The given parameter is
Perimeter, P = 520 feet
Represent the shorter side with x and the longer side with y
One side of the garden is bordered by a river:
So the perimeter is:
P = 2x + y
Substitute P = 520
2x + y = 520
Make y the subject
y = 520 - 2x
The area is
A = xy
Substitute y = 520 - 2x in A = xy
A = x(520 - 2x)
Expand
A = 520x - 2x^2
Differentiate
A' = 520 - 4x
Set to 0
520 - 4x = 0
Rewrite as:
4x= 520
Divide by 4
x= 130
Substitute x= 130 in y = 520 - 2x
y = 520 - 2 *130
Evaluate
y = 260
The area is then calculated as:
A = xy
This gives
A = 130 * 260
Evaluate
A = 33800
Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
Read more about area at:
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You have some unknown integer

, and you know that adding this and the next two integers,

and

, gives a total of 57.
This means

The task is to find all three unknown integers. Notice that if you know the value of

, then you pretty much know the value of the other three integers.
To find

, solve the equation above:

So if 18 is the first integer, then others must be 19 and 20.
Answer:
2
Step-by-step explanation:
Degree is the highest power of a term
I hope im right!
Answer:
<em>w</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>
Step-by-step explanation:
Solving steps are shown in above pic. (source: Photomath)
Answer: Randomly assign the 1,200 students to <u>6 equal-sized</u> groups. Then select one of the groups and place their names in the bin. Randomly select the winner from the bin.
Step-by-step explanation:
First, let us see how many bins we will need in total.
1,200 students / 200 notecards per bin = 6 bins
Now, the first two options do not give all students a fair chance of winning. They are not our answer.
The last two have a different number of groups. Looking at the calculation we did earlier, we will need 6 equal-sized groups. This means our answer is the last option.