Answer: Lower left corner
A piecewise function is basically a combination of other functions to make one single function. We can break up the given piecewise function into two parts:
f(x) = x-4
OR
f(x) = -2x
The f(x) will change depending on what x happens to be. If x is 0 or smaller, then we go with f(x) = x-4. Otherwise, if x is larger than 0, then we opt for f(x) = -2x.
To graph this, we basically graph y = x-4 and y = -2x together on the same coordinate system. We only graph y = x-4 if x is 0 or smaller. Likewise, we graph y = -2x when x > 0. This results in the graph shown in the lower left corner of your four answer choices.
Note: the closed circle means "include this point as part of the graph". The open circle means "exclude this point as part of the graph". So this is why the upper right corner is very close but not quite the answer we want.
Answer:
240 more girls
Step-by-step explanation:
210 + 160 = 370
100 + 30 = 130
370 - 130 = 240
Answer:
1. True
2. False
3. True
4. False
5. True
Step-by-step explanation:
1. For a real number a, a + 0 = a.
This is true, any number plus zero is that number.
2. For a real number a, a + (-a) = 1.
This is false. Adding a negative number is the same as subtracting that number. So a + (-a) = a - a = 0
3. For a real numbers a and b la-bl = |b-al.
This is true. Absolute value represents the distance between two numbers. This number can never be negative, therefore la-bl = |b-al.
4. For real numbers a, b, and c, a +(bº c) = (a + b)(a + c).
False. a + (b * c) = a + bc.
If you foil (a + b)(a + c) you will see its equal to a²+ab+ac+bc, which is definitely different than a + (b*c)
5. For rational numbers a and b when b# o, is always a rational number.
True, a rational number is one that can be written as a fraction with two integers. The quotient of two rational numbers can always be written as a fraction with integers.
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-9)^2+y^2=4\implies (x-\stackrel{h}{9})^2+(y-\stackrel{k}{0})^2=2^2~\hfill \stackrel{center}{(9,0)} \\\\\\ (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=4\implies (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=2^2~\hfill \stackrel{center}{(3,2)}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%7D%7B%20r%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%28x-9%29%5E2%2By%5E2%3D4%5Cimplies%20%28x-%5Cstackrel%7Bh%7D%7B9%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B0%7D%29%5E2%3D2%5E2~%5Chfill%20%5Cstackrel%7Bcenter%7D%7B%289%2C0%29%7D%20%5C%5C%5C%5C%5C%5C%20%28x-%5Cstackrel%7Bh%7D%7B3%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B2%7D%29%5E2%3D4%5Cimplies%20%28x-%5Cstackrel%7Bh%7D%7B3%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B2%7D%29%5E2%3D2%5E2~%5Chfill%20%5Cstackrel%7Bcenter%7D%7B%283%2C2%29%7D)
Check the picture below.
well, its radius didn't change, anyhow, you know what to check out.
