All categories

2 years ago

Simplify 7 sqare root 3 takeaway 2 sqare root 3 add sqaure root 3 takeaway 3 sqaure root 3

Mathematics

1 answer:

Paha777 [63]2 years ago

8 0

Answer:

tel:+18446450594

Step-by-step explanation:

You might be interested in

What is the LCM of 7 and 13

lutik1710 [3]

Answer:

91 .

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly. Glad I could help!!

3 0

3 years ago

Which ordered pairs are solutions to the inequality 2x+y>−4?

hichkok12 [17]

we will proceed to resolve each case to determine the solution

we have

$2x+y>-4$

$y>-2x-4$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-12)$

Substitute the value of x and y in the inequality

$-12>-2*5-4$

$-12>-14$ ------> is True

therefore

the ordered pair $(5,-12)$ is a solution of the inequality

case b) $(-3,0)$

Substitute the value of x and y in the inequality

$0>-2*-3-4$

$0>2$ ------> is False

therefore

the ordered pair $(-3,0)$ is not a solution of the inequality

case c) $(-1,-1)$

Substitute the value of x and y in the inequality

$-1>-2*-1-4$

$-1>-2$ ------> is True

therefore

the ordered pair $(-1,-1)$ is a solution of the inequality

case d) $(0,1)$

Substitute the value of x and y in the inequality

$1>-2*0-4$

$1>-4$ ------> is True

therefore

the ordered pair $(0,1)$ is a solution of the inequality

case e) $(4,-12)$

Substitute the value of x and y in the inequality

$-12>-2*4-4$

$-12>-12$ ------> is False

therefore

the ordered pair $(4,-12)$ is not a solution of the inequality

Verify

using a graphing tool

see the attached figure

the solution is the shaded area above the line

The points A,C, and D lies on the shaded area, therefore the ordered pairs A,C, and D are solution of the inequality

7 0

3 years ago

Read 2 more answers

tigry1 [53]

4) What is the question

6 0

2 years ago

Jamal borrowed $316 for nine months. He paid it off by paying $38.27 monthly.

Doss [256]

$28.43 is the answer

7 0

2 years ago

Read 2 more answers

Find the length of the radius of the circle whose perimeter is xcm and the area is

Jobisdone [24]

$\bf \stackrel{\textit{perimeter}}{\textit{circumference}}\textit{ of a circle}\\\\ C = 2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=x \end{cases}\implies x = 2\pi r\implies \boxed{\cfrac{x}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=x \end{cases}\implies x = \pi \left( \boxed{\cfrac{x}{2\pi }} \right)^2\implies x = \pi \cdot \cfrac{x^2}{2^2\pi^2}$

$\bf x = \cfrac{x^2}{4\pi }\implies 4\pi x = x^2\implies \cfrac{4\pi x}{x}=x\implies \blacktriangleright 4\pi = x\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since the radius is}}{r = \cfrac{x}{2\pi }}\implies r =\cfrac{4\pi }{2\pi }\implies \blacktriangleright r = 2\blacktriangleleft$

6 0

3 years ago

Read 2 more answers