It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
Answer:
Option E is correct.
- Treatments: how the peppermint oil is dispersed
- Experimental unit: mice
- Response variable: number of mice in the dwellings
Step-by-step explanation:
The treatments in this type of statistical experiment refers to the part of the experiment that is tweaked, controlled or varied in the cases being studied. In this experiment, the method of essential oil dispersal is what is varied in the two experimental cases of this study.
Experimental Unit refers to the subject matters, who are participants in the experiment. They are the ones that the effect of the treatments is tested upon.
For this study, the experimental units are the mice subjected to either of the two methods of peppermint oil dispersal.
The response variable is how the experimental units (participants) respond to the treatments (experimental tweaks). Or how the tweaks manifest observable results in the participants of the study. For this study, the effect of the tweaks in the mice is shown in the number of mice that remain in each dwelling (where the two methods of peppermint oil dispersal have been implemented). Hence, the response variable is the number of mice in each dwelling.
Hope this Helps!!!
The answer is C. and E.
--
Work shown below:
A. 500 divided by 6 equals 83.33.
B. 600 divided by 3 equals 200.
C. 100 divided by 4 equals 25. (CORRECT)
D. 150 divided by 5 equals 30.
E. 200 divided by 8 equals 25. (CORRECT)
--
Hope this could help you.
Use an online math calculator for more accurate answers just plug in the variables
Answer:
<em>We can't find a unique price for an apple and an orange.</em>
Step-by-step explanation:
Suppose, the price of an apple is 
and the price of an orange is 
They need $10 for 4 apples and 4 oranges. So, the first equation will be.......
They also need $15 for 6 apples and 6 oranges. So, the second equation will be........
Dividing equation (1) by 2 on both sides : 
Dividing equation (2) by 3 on both sides : 
So, we can see that both equation (1) and (2) are actually same. That means, we will not get any unique solution for and here. Both and have <u>"infinitely many solutions"</u>.
Thus, we can't find a unique price for an apple and an orange.
