Hello,
1)Let's call A=inter (4x-y-7=0, x+3y-31=0)
4x-y=7
x+3y=31
==>13x=52==>x=4
and y=4*4-7=9
A=(4;9)
2)Let's call B=inter (4x-y-7=0, x+5y-7=0)
4x-y=7
x+5y=7
==>21x=42
==>x=2 and y=4*2-7=1
B=(2,1)
3) Slope of BD: y=-x/3+31/3 ==> slope perpendicular=3
Line BD:y-1=3(x-2)==>y=3x+5
4) Slope AE: y=-x/5+7/5 ==>slope perpendicular=5
Line AE: y-9=5(x-4)==> y=5x-11
5) intersection (BD;AE):
y=5x-11
y=3x-5
==>2x=6==>x=3
and y=3*3-5=4
H=(3,4)
Answer:
10
Step-by-step explanation:
First, factorize the number 3,240:

So,

Now consider the fraction

If k = 10, then

is a square number.
For all k < 10, the fraction tex]\dfrac{3,240}{k}[/tex] is not a square number (this follows from factorization).
Or you can simply check the values of the fraction for all k < 10:
- k = 1,
is not a square number; - k = 2,
is not a square number; - k = 3,
is not a square number; - k = 4,
is not a square number; - k = 5,
is not a square number; - k = 6,
is not a square number; - k = 7,
is not a square number; - k = 8,
is not a square number; - k = 9,
is not a square number.
Answer:
x = 66
Step-by-step explanation:
For a set of N numbers:
{x₁, x₂, ..., xₙ}
The mean can be calculated as:

In this case we have the data set:
{98, 122, 104, 115, 107, x}
And I assume that we want to have the mean = 102.
So we have a set of 6 numbers, the mean of this set will be:

We need to solve this equation for x.
If we multiply both sides by 6, we get:
(98 + 122 + 104 + 115 + 107 + x) = 102*6 = 612
546 + x = 612
x = 612 - 546 = 66
x = 66
Answer:
x = -6
Step-by-step explanation:
Let the number be x
<u>Condition:</u>
=> 10-3x = x+22
<u><em>Let's Solve it:</em></u>
=> -3x-x = 22-10
=> -2x = 12
<em>Dividing both sides by -2</em>
=> x = -6