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Dafna11 [192]
4 years ago
6

On Monday, the value of a stock decreased by 1/2 point. On Tuesday, the value increased by 3/4 point. On Wednesday, the value de

creased by 3/8 point. What number represents the change in stock value after three days?
Mathematics
2 answers:
swat324 years ago
5 0
Lo que el jueves es 4/12 talvez???

Feliz [49]4 years ago
4 0

Answer: There is decreased by 1\dfrac{5}{8} points in stock after three days and negative integer is used to represent.

Step-by-step explanation:

Since we have given that

Point decreased by on Monday = \dfrac{1}{2}

Point decreased by on Tuesday = \dfrac{3}{4}

Point decreased by on Wednesday = \dfrac{3}{8}

So, total decreased in these three days are

\dfrac{1}{2}+\dfrac{3}{4}+\dfrac{3}{8}\\\\=\dfrac{4+6+3}{8}\\\\=\dfrac{13}{8}\\\\=1\dfrac{5}{8}

hence, there is decreased by 1\dfrac{5}{8} points in stock after three days and negative integer is used to represent.

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sp2606 [1]

Answer:

35%

Step-by-step explanation:

79.99-51.99=29/79.99-.35 rounded

7 0
3 years ago
The polar form of this is?
prohojiy [21]

Answer:

2, 120 degrees

Step-by-step explanation:

The first step in finding the polar form is finding the modulus, r

r= sqrt( x^2 + y^2)

r = sqrt( (-1)^2 + sqrt(3)^2)

r = sqrt(1+3)

r= sqrt(4)

r =2


The next step is finding the angle

theta = arctan (y/x)

theta = arctan (sqrt(3)/-1))

theta = arctan (-sqrt(3))

theta = -60


The point (-1, sqrt(3)) is in the 2nd quadrant, but our angle is in the 4th quadrant, so we add 180 degrees

theta = -60 + 180 = 120

theta = 120 degrees

6 0
3 years ago
Need help what the awnser is.<br>b - 6 = 21​
Alex787 [66]
27 hope this helps!!!
3 0
3 years ago
PLEASE HELP ME!! ILL GIVE BRAINLIEST!!
Natalka [10]

Answer:

C

Step-by-step explanation:

1/4 is .25

4 fourths is 1. 4 times 7 equals 28 hamburgers. one half is two fourths. 28+2=30 hamburgers.

6 0
2 years ago
Read 2 more answers
Can I please get some help on this...I have tried to many times...
Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

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3 years ago
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