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Alexxx [7]
2 years ago
11

Write 5-7 well-written sentences. REREAD FOR ERRORS AND FIX THEM!! If you could spend the perfect day, what would you do? Where

would you be? Who would be with you? What do you see? Eat? Play? Use your senses to describe it? What do you see? Hear? Smell? Taste? Touch?
Mathematics
1 answer:
Lyrx [107]2 years ago
4 0

Answer:

  1. If i could spend the perfect day I would go to the park and take a jog. I would also go to Mc donalds and get a vanilla flavored ice cream! I love the taste of vanilla, Next, i will watch my favorite movie on my phone. Then, i will go to the zoo with my friends and see my favorite animals! Lastly,i will go home and take a nap.

Step-by-step explanation:

okay

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Walter is 43 years old his daughter Paulette is 7. In how many years will Paulette be one-third of Walters age
Ksju [112]
The answer is 14 when rounded to the nearest whole number, to get this you simply must divide 43 by 3 which equals to 14.333. 

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Which expression would you use to determine the missing number in the sequence? 12, ____, 26, 33, 40
Paladinen [302]

Answer:

The answer is 19.

Step-by-step explanation:

This is because the sequence adds up by 7 each time. Have a nice day!

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2 years ago
Read 2 more answers
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

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It would be 12 nickels and 9 dimes

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