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2 years ago

Given the lease terms below, what is the total price of this car if you buy it

Mathematics

2 answers:

balu736 [363]2 years ago

7 0

12,342 I think..........

strojnjashka [21]2 years ago

5 0

Answer:

I believe the answer is 12,342 try it out and let me know:)

Step-by-step explanation:

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PLS HELP 100 POINTS!!!!!!!!!!!!!!! A female orca eats 125 kilograms of marine animals each day. At this rate, how many days will

Yuliya22 [10]

Answer:

31 days

Step-by-step explanation:

125 kg/1 day = 3875 kg/x days

x(125) = 3875

x = 3875/125

x = 31 days

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%

Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

$I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx$

Replace $x \to x^{\frac1\phi} = x^{\phi-1}$ :

$I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

Split the integral at x = 1. For the integral over [1, ∞), substitute $x \to \frac1x$ :

$\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

The integrals involving tan⁻¹ disappear, and we're left with

$I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}$

8 0

2 years ago

A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students

aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, $H_0$ : $p_1 = p_2$ {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, $H_1$ : $p_1 > p_2$ {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

$\frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } }$ ~ N(0,1)

Here, $\hat p_1$ = No. of students passed the exam ÷ No.of Students that had taken the course

$\hat p_1$ = $\frac{1150}{1850}$ Similarly, $\hat p_2$ = $\frac{1440}{1500}$ $n_1$ = 1,850 $n_2$ = 1,500

Test Statistics = $\frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } }$ = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0

2 years ago

If $2940 is invested at 3.2% compounded quarterly, how much is in the account after 8 years?

tino4ka555 [31]

Answer:

The future value is $3793.776

Step-by-step explanation:

Given

$PV = 2940$ --- present value