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DENIUS [597]
3 years ago
10

What is the correct written expression for the variable expression: (3 - x)/7

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0
<h2>The answer is:</h2>

<h3>The difference if 3 divided by 7 and x</h3>

<h2>Hope it was helpful to you </h2>
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For the polynomial, list each real zero and its multiplicity. Determine whether the graph
SVEN [57.7K]

Answer:

A, B, F

Step-by-step explanation:

took the test

6 0
3 years ago
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Given: -1/2x &gt; 6.<br><br> Choose the solution set.
kompoz [17]

Answer:

x < -12

Step-by-step explanation:

-1/2x > 6

Multiply by -2 to isolate x

Remember that when multiplying by a negative, we flip the inequality

-2 * -1/2x < 6*-2

x < -12

4 0
3 years ago
Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1
Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

f(x) = x^3+6x-5

For x = 0. the value of the expression is:

f(0) = 0^3+0-5\\f(0) = -5

For x = 1, the value of the expression is:

f(1) = 1^3+6-5\\f(1)=2

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0
3 years ago
I AM GIVING 45 POINTS TO WHOEVER GETS THIS RIGHT... plz answer corectly and try... i was working on this for sooo long. Plz try
Alexxx [7]
When you have 3 choices for each of 6 spins, the number of possible "words" is
  3^6 = 729

The number of permutations of 6 things that are 3 groups of 2 is
  6!/(2!×2!×2!) = 720/8 = 90

A) The probability of a word containing two of each of the letters is 90/729 = 10/81


The number of permutations of 6 things from two groups of different sizes is
  (2 and 4) : 6!/(2!×4!) = 15
  (3 and 3) : 6!/(3!×3!) = 20
  (4 and 2) : 15
  (5 and 1) : 6
  (6 and 0) : 1

B) The number of ways there can be at least 2 "a"s and no "b"s is
  15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.


_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
6 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY MATH ASAP PLEASE!!!!​
densk [106]

Answer:

5

Step-by-step explanation:

The height of the largest triangle = √(9 * 25) = 3 * 5 = 15

y is the square root of (25^2 + 15^2)

y = √(625 + 225)

y = √850

y = √(2 * 5*5 * 17)

y = 5 * √34

5 goes in the box.

8 0
3 years ago
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