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BARSIC [14]
3 years ago
10

WILL GIVEBRALIST TO FIRST ONE

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

i think D

Step-by-step explanation:

not 100% but 99% cause im not a genius :/ <------------------ I GOT IT WRONG DONT USE THIS ANSWER

torisob [31]3 years ago
3 0
Rectangle explanation:I’m doing the same thing
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Determine the y intercept for the following equation y=2x-8
Orlov [11]

Answer: The y-intercept is -8

Step-by-step explanation:

It's simple to understand once you memorize the slope intercept formula!

y=mx+b

m stands for the slope which is rise/run

The b is the y-intercept, which is the answer you are looking for! the y-intercept is where the line crosses the y-axis!

3 0
3 years ago
Andrew bought 3 boxes of granlla bars. There are 13 granola bars in each box. choose the expression that shows how many granola
noname [10]

Answer:

13b

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Halla dos pares de enteros cuya suma sea -6​
SCORPION-xisa [38]

Answer:

0 y -6 o 1 y -7

Step-by-step explanation:

7 0
3 years ago
18-2x=4x drag AND drop the reasons into the boxes to correctly complete the table.
scoundrel [369]
18-2x=4x is given
18=6x is addition property of equality
3=x is I think division property of equality bc you divided to get x=3
4 0
3 years ago
2. Determine the sum of the first 400 ODD numbers.<br><br>​
il63 [147K]

Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

S=1+3+5+\cdots+795+797+799

By reversing the order of terms, we have

S=799+797+795+\cdots+5+3+1

and we can pair up terms in both sums at the same position to write

2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

2S=400\cdot800\implies S=160,000

###

We could also make use of the formulas,

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2

We have

S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

3 0
3 years ago
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