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Zielflug [23.3K]
3 years ago
15

Find the quotient of 1 1/4 and 3 1/2 express your answer in simplest form

Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0

11/14 is the answer! (Quotient in simplest form)

natta225 [31]3 years ago
4 0

Answer:

11/14

Step-by-step explanation:

11/4 / 3 1/2

3 1/2= 3*2+1= 6+1=7/2

11/4 * 2/7= 22/28

22/2=11

28/2= 14

11/14

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Answer:

Step-by-step explanation:

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3 0
3 years ago
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An expression is shown below. Which expression is equivalent to the expression shown?
Vera_Pavlovna [14]

Note: In option A, it should be "+" instead of "(".

Given:

The expression is

-2x(x+y-3)+3(-x+4y)+y(3x+5y-3)

To find:

The equivalent expression.

Solution:

We have,

-2x(x+y-3)+3(-x+4y)+y(3x+5y-3)

Using distributive property, we get

=-2x(x)-2x(y)-2x(-3)+3(-x)+3(4y)+y(3x)+y(5y)+y(-3)

=-2x^2-2xy+6x-3x+12y+3xy+5y^2-3y

On combining like terms, we get

=-2x^2+5y^2+(-2xy+3xy)+(6x-3x)+(12y-3y)

=-2x^2+5y^2+xy+3x+9y

The expression -2x^2+5y^2+xy+3x+9y is equivalent to the given expression.

Therefore, the correct option is A.

6 0
3 years ago
2x-5y=3 4y-x=-3 solve by elimination
loris [4]

Answer:

x = -1 and y = -1

Step-by-step explanation:

to solve this equation we say

let

2x-5y=3.......................................... equation 1

4y-x=-3............................................equation 2

from equation 2

4y-x=-3............................................equation 2

4y + 3 = x

i.e

x = 4y + 3 .............................................  equation 3

put x = 4y + 3 in equation 1

2(4y +3) - 5y = 3

8y + 6 -5y = 3

3y +6 = 3

3y= 3-6

3y -3

divide both sides by the coefficient  of y  which is 3

3y/3 = -3/3

y = -1

put y = -1 into equation 3

x = 4y + 3 .............................................  equation 3

x = 4(-1) + 3

x = -4 + 3

x = -1

therefore the value of x = -1 and y = -1 respectively

4 0
3 years ago
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

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Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
4 years ago
How far apart are the foci of an ellipse with a major axis of 20 feet and a minor axis of 14 feet?
omeli [17]
The solution for this question is simple. First we need to divide both numbers by 2 which will give us 10 and 7. This is the equation x^2/10^2 + y^2/7^2 = 1sqrt(100-49) = 7.14 (the answer do not have a perfect square root)
Foci are 14.28 units apart 
3 0
3 years ago
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