Substitute x = -5
|2* -5 -1| + 10
|-10-1| + 10
21
Answer:
1.- 140 in²
2.- 2.25 in²
3.- 43.25 in²
4.- 7.5 in²
5. 349.75 in²
Step-by-step explanation:
4 congruent triangles mean 4 triangles same measurement
area 1 triangle=(B*H)/2=(10*7)/2=35in²
for area of the roof are 4 by area 1 triangle=4*35=140 in²
2.- area hole. Hole is a square so area Is side by side
area=1.5*1.5=2.25
3.- area front except the hole. As the side of front is isosceles trapezoide which it’s area is (B1+B2)H/2 where B1=8 in and B2=5 in and H=7 in
so arera with hole=(8+5)*7/2=45.5 in²
Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
Answer:
15
Step-by-step explanation:
we need to write the equation. I came up with....
3(5 - x) = 30
so take the 3 away from the 30. I think your not supose to do the 3 because it out of the ( ). the opppisite of multiplication is division. so...
3 divided by 30 =10
rewrite
(5 - x) = 10
take the 5 away. the oppisite of subbtraction is addition.
5 + 10 = 15
check your; plug in x
3(5 - 15) = 30 This equation looks true!
Hope this helped! Please mark as brainliest! Thanks
Answer:
Yes
Step-by-step explanation:
Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.
