All categories

2 years ago

Using the triangle theorem solve this triangle.

Mathematics

2 answers:

Vera_Pavlovna [14]2 years ago

8 0

Answer:

OK THIS IS A BIGGY....c = 8

Step-by-step explanation:

First, find b.

using the pythagorean theorem, a² + b² = c²

to find b using an angle, do b = √(c² - a²)

then, b = a * tan(β)

(β is the angle 30°)

So, b = 6.928

Then, plug it into the pythagorean theorem

4² + 6.928² = c²

16 + 47.997184 = c²

63.997184 = c²

√63.997184 = √c

c = 7.99982399806

Rounded is 8 :)

Hope this helps! Please mark as brainliest :)

ratelena [41]2 years ago

6 0

Answer:

b = 4 $\sqrt{3}$ , c = 8

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = $\frac{1}{2}$ , then

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{4}{c}$ = $\frac{1}{2}$ ( cross- multiply )

c = 8

Using Pythagoras' identity in the right triangle

b² + 4² = 8²

b² + 16 = 64 ( subtract 16 from both sides )

b² = 48 ( take the square root of both sides )

b = $\sqrt{48}$ = $\sqrt{16(3)}$ = 4 $\sqrt{3}$

You might be interested in

Molly is making peanut butter cookies. To make a batch of cookies she needs cups of peanut butter, 1.5 cups of sugar, and 1 egg.

Rina8888 [55]

Answer:

4 batches

Step-by-step explanation:

one batch calls for:

3/4 PB

1 1/2 cup SG

1 EGG

3/.75(3/4)= 4

9/1.5(1 1/2)=6

5/1= 5

The maximum number of batches she can make before running out of ingredients is 4

6 0

3 years ago

Sarah has $18.00 and she earns $7.25 an hour at work. what’s the equations

BigorU [14]

Answer:

y = 7.25x + 18

Step-by-step explanation:

18 is the base. so it goes last.

7.25 is the amount being raised per a certain amount (hours) so its 7.25x

6 0

3 years ago

PLZ HELP ME W THIS !!! MARKIN BRAINIEST !!!

satela [25.4K]

Answer:

Step-by-step explanation:

5 0

3 years ago

(12x + y + z = 26

mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

$\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}26\\17\\23\end{array}\right]$ .

Step 3:

The linear system B is represented as

$\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}23\\17\\26\end{array}\right]$ .

Step 4:

The linear system C is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}4\\11\\12\end{array}\right]$ .

Step 5:

The linear system D is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}12\\11\\4\end{array}\right]$ .