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scoray [572]
3 years ago
6

Can someone help me please?

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
So, you start by separating the equation into two inequalities and you get
4x+1 > -7 and 4x +1 < 5

Solve these inequalities and you get your final answer:
x > -2 and x < 1

(The equalities symbols are supposed to have the "or equal" line beneath them, I was just too lazy to put them.)

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Solve the following system of equations: (1 point) x − 2y = 14 x + 3y = 9
kifflom [539]
1y=14x+9 I this it’s one is the answer
4 0
3 years ago
Solve In (2x+3)=7 round to the nearest thousandth
e-lub [12.9K]
To solve this problem you must apply the proccedure shown below:

 1. You have:
<span>
 In(2x+3)=7

 2. Then, you must apply log(e), as below:
</span><span>
 In(2x+3)=ln(e^7)

 3. Now, you obtain:

 2x+3=e^7

 4. Youy must clear the variable "x", as below:

 2x=e^7-3
</span> x=(e^7-3)/2
<span>
 5. Therefore, the value of "x" is:

 x=546.817
</span><span>
 The answer is: </span>x=546.817<span> </span>
8 0
3 years ago
3/8-(-51/4) simplest form
Ratling [72]

Answer:

13 1/8

Step-by-step explanation:

3/8-(-51/4)

Subtracting a negative is like adding

3/8 + 51/4

get a common denominator

3/8+ 51/4 *2/2

3/8 + 102/8

105/8

8 goes into 105 13 times with 1 left over

13 1/8

3 0
3 years ago
In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect and . Then, i
ss7ja [257]

The measure of ∠ABP and ∠ABC are 32° and 64° respectively.

<h3>what is a bisector of an angle?</h3>

Any line which divides an angle into two equal halves is a bisector of that angle.

Analysis:

Since the arcs at D and E are drawn with the same radius and arc using center D and E are intersected by line PB( which is the bisector of the full arc with center B) then ∠ABP = ∠PBC = 32°.

∠ABC = ∠ABP + ∠PBC

∠ABC = 32 + 32 = 64°

In conclusion, ∠ABP and ∠ABC are 32° and 64°

Learn more about bisectors of angles: brainly.com/question/24334771

#SPJ1

3 0
2 years ago
How many solutions does the following equation have ?<br> −3x+9−2x=−12−5x
nasty-shy [4]

\text{Solve for x:}\\\\-3x+9-2x=-12-5x\\\\\text{Combine like terms}\\\\-5x+9=-12-5x\\\\\text{Add 5x to both sides}\\\\9=-12\\\\\text{Since that's not valid, there would be no solutions}\\\\\boxed{\text{No solutions}}

7 0
3 years ago
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