All categories

3 years ago

Find the measure of one interior angel if a regular 23-gon

Mathematics

1 answer:

Anit [1.1K]3 years ago

3 0

The 23 <em>exterior</em> angles add to 360. The interior angles are supplements of the exterior angles.

180 - 360/23 = 3780 / 23 = 164.3478...

Answer: a

You might be interested in

Round fraction as a decimal round three decimals place 6/13

frez [133]

Round fraction as a decimal: 6/13=.462 that's the answer

6 0

2 years ago

It costs $5.15 to rent a kayak for 1 hour at a local state park. The price per hour stays the same for up to 5 hours of rental.

iren [92.7K]

5.15 x 5 = 25.75

25.75 + 3.75 = 29.5

So your answer is $29.50

Hope it helps! :D

6 0

2 years ago

A rectangle is 3 times as long as it is wide. the perimeter is 16 feet. find the dimensions

astraxan [27]

Answer:

Width = 2 feet

Length = 6 feet

Explanation:

Variables:

Perimeter = p

Length = l

Width = w

Equation:

2w + 2l = p

It is given that:

l = 3w

and

p = 16 feet

With this information, we can rewrite the equation (substitute)

2w + 2(3w) = 16

Simplify

2w + 6w = 16

Add

8w = 16

Divide both sides of the equation by 8

Width = 2 feet

Length = 3(w) = 3(2) = 6 feet

Hope this helps :)

6 0

2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

7 0

3 years ago

At a convention of science teachers, various attendees are asked to name their favorite subject in high school.

solong [7]

C teacher survey because that

6 0

2 years ago