Answer:
1) C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) Continuous
Step-by-step explanation:
1) The given parameters are;
The base fee charged = $25
The amount charged for labor = $40/hour
The total cost for h number of hours is C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) The situation is continuous because the different input values of h can be infinite (from o to infinity)
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

C=d x pi
d= 24
C= 24 x 3.14
C=75.36 inches
hope this helps