Question

The length of a triangel is three times its with.if the perimiter is at its most 112 centemeters,witch is the greates possible value of the with.
a.2w+2*(3w)$\leq$112
b. 2w+2*(3w)<112
c. 2w+2*(3w)>112
d.2w+2*(3w)$\geq$112

Answer 1

I am assuming you do not mean The length of a triangle and you mean The length of a rectangle because the answer you given are the formula for the perimeter of a rectangle. With that said, the answer is D.2w+2*(3w)112

The perimeter of a rectangle can be found by the following equation:

2L + 2W = P
OR 
P = 2L + 2W
The equation P = 2L + 2W is read perimeter = 2 times Length + 2 times width

The Question:
The length of a rectangle is three times its width.if the perimeter is at its most 112 centimeters ,which is the greatest possible value of the the width.

The length of a rectangle
This means the perimeter 

is
The word is means to use an equal sign

three times its width
This means 3 times w or 3w 
The w = width

perimeter is at its most 112
This means <=
<= means less than or equal to

Ok so lets look at our equation 

2L + 2W = P
2w + 2(3w) <= 112