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umka21 [38]
3 years ago
6

In the number 9,999.999, how does the 9 in the tens place compare to the 9 in the place to its left. The 9 in the tens place rep

resents of what the 9 to its left represents. The 9 in the tens place represents of what the 9 to its left represents. The 9 in the tens place represents 10 times what the 9 to its left represents. The 9 in the tens place represents 100 times what the 9 to its left represents.
Mathematics
1 answer:
aleksley [76]3 years ago
6 0

The question is not complete as the options are not correct. However, the correct answer is as follows:

Answer:

The correct answer is - the 9 in the tens place represents 1/10 times what the 9 to its left represents.

Step-by-step explanation:

Given:

Number:   9999.999

We know: The tenth value is 99<u>9</u>9.999 (in bold) and 9 to its left is underlined which is the 100th value.

Solution:

Place value of 9 on the tenth place

= 9*10= 90 ..... 1

Left place of the tenth is hundredth

Place value of 9 at the hundredth place

=9*100

=900 .... 2

comparing 1 to 2 by dividing

= 90/900

= 1/10th

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4x plus 20y

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4 times x  plus 20xy

4x plus 20y

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In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from
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Answer:

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation  

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

\hat p=\frac{135}{420095}=0.0003214 estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

p_o=0.00034 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :  

Null hypothesis:p=0.00034  

Alternative hypothesis:p \neq 0.00034  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.  

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