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Effectus [21]
3 years ago
15

-52/3 • (-2 576) Pls help :D

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Step-by-step explanation:

-5⅔×(-2⅚)

-17/3×(-17/6)

289/18

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Algebra 2! please help!
valentina_108 [34]

Answer:

Choice C)

x^2 - 2x + 4 - 12/(x+2)

x^2 - 2x + 4 - \frac{12}{x+2}

====================================================

Explanation:

To see how I got that answer, I have provided two attached images below. One of them shows the polynomial long division. The other shows synthetic division. Both are valid options to get to the same answer.

For each method, I used 1x^3 + 0x^2 + 0x - 4 in place of x^3 - 4 so that the proper terms could align.

6 0
3 years ago
What is the following simplified product? Assume
Yanka [14]

<u>Answer:</u>

The correct answer option is D. 10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}.

<u>Step-by-step explanation:</u>

We are given the following expression:

\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )

Assuming that x\geq 0, we are to find its simplified product.

\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )

\\\\ = 2 \sqrt { 150 x ^ 8 } + \sqrt { 3 0 x ^ 7 }-2x\sqrt{75x^6}-x\sqrt{15x^5} \\\\ =2\sqrt{25\times6x^8}+x^3\sqrt{30x}-2x\sqrt{25\times3x^6}-x^3\sqrt{15x} \\\\ =10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

4 0
3 years ago
Read 2 more answers
Question 17
RoseWind [281]

Answer:

Perpendicular

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are the same.
  • Two lines are perpendicular is their slopes are negative reciprocals.
  • And two lines are neither (a.k.a intersecting) if they are neither parallel nor perpendicular.

So, let's find the slope of QR and ST.

QR)

We can use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let Q(-6, 11) be (x₁, y₁) and R(2, -1) be (x₂, y₂). Substitute:

m=\frac{-1-11}{2-(-6)}

Subtract:

m=-12/8=-3/2

So, the slope of QR is -3/2.

ST)

Let S(-4, 8) be (x₁, y₁) and T(-1, 10) be (x₂, y₂). Substitute:

m=\frac{10-8}{-1-(-4)}

Subtract:

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So, the slope of ST is 2/3.

The negative reciprocal of -3/2 is 2/3.

And the negative reciprocal of 2/3 is -3/2.

So, the slopes are indeed negative reciprocals of each other.

So, QR and ST are perpendicular.

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A. Is the correct answer for the question.
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