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Molodets [167]
3 years ago
9

Find any real solutions for the following equations. sqrt(x) = -1

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0
The sqrt of (x)=-1 is either i or 1
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Make double add 9+8=
vfiekz [6]

so maybe 6 plus 3 which equals 9. Then add 8 at the end

6 0
4 years ago
*URGENT* which answer is a solution to the inequality?
Bad White [126]
Try them and see.

For the first:
  3(-3) + 0 = -9 . . . . not > -8
  3(-2) + (-1) = -7 . . . is > -8 . . . . . 2) (-2, -1) is a solution

For the second:
  4 - 4(-2) = 12 . . . . not ≤ -6
  -2 -4(1) = -6 . . . . . is ≤ -6 . . . . . . 2. (1, -2) is a solution
7 0
3 years ago
20 points and brainlist if correct!
weeeeeb [17]

Answer:

The Commutative property states that numbers can be multiplied in any order

Step-by-step explanation:

look at the equation 4x2.36x.25. If you write the equation differently as 4x.25x2.36, the equation becomes easier to solve. Why? As you can see 4 and .25 (aka 1/4) 4 and 1?4 are reciprocals and anything multiplied by the reciprocal is 1. so 1x 2.36 is  2.36. The Communicative Property just helps to see those patterns and connections

hope this helps ;)

6 0
3 years ago
Jane took 20 minutes to drive her boat upstream to water Skeeter favorite spot coming back later in the day at the same boat spe
Natasha2012 [34]
1/40 km per minute is the correct answer
6 0
3 years ago
A helium-filled blimp stays aloft since helium is less dense than regular air, so helium will rise above regular
worty [1.4K]

Answer:

The blimp can carry 70 passengers

Step-by-step explanation:

Lets use the ratio method to solve this problem

∵ 1 cubic meter of helium  can lift about 1.1 kg

∵ A blimp can carry as much as 2 x 10^{5} m³ of helium

By using the ratio method

→  m³         :  kg

→  1            :  1.1

→  2 x 10^{5}   :  x

By using cross multiplication

∴ x × 1 = 1.1 × 2 x 10^{5}

∴ x = 2.2 x 10^{5}

∵ x represents the mass that can carried by the helium

∴  2 x 10^{5} m³ of helium can lift 2.2 x 10^{5} kg

∵ The mass of the blimp is 2.13 x 10^{5} kg

- Subtract the mass of the blimp from the mass that the given

    amount of helium can lift to find the mass of the passengers

∴ The mass of the passengers = 2.2 x 10^{5} - 2.13 x 10^{5}

- Subtract 2.13 from 2.2 ⇒ 2.2 - 2.13 = 0.07

∴ The mass of the passengers = 0.07 x 10^{5}

∵ The average mass of a person with luggage is 10² kg

- Divide the mass of the passengers by the mass of the person

   to find the number of the passengers

∴ The number of passengers = 0.07 x 10^{5} ÷ 10²

- Subtract the exponents of 10 to find the answer

∵ 10^{5} ÷ 10² = 10^{5-2} = 10³

∴ The number of passengers = 0.07 x 10³

∴ The number of passengers = 0.07 × 1000

∴ The number of passengers = 70

The blimp can carry 70 passengers

3 0
3 years ago
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