Ask question

Ask question

All categories

3 years ago

11

Literal Equations? Anyone? The problems are in the picture! Show solution please! Thanks in advance!

1 answer:

lapo4ka [179]3 years ago

4 0

The way to solve is using order of operation PEMDAS. Its very easy. You should be able to solve it yourself. I'll give you the first 3 answers:
1. g/6=x
2. x=1/2u+1
3. z-m=x
I would give you all the answers but it would be best if you did it yourself. You teacher and parents would be much happier if you learnt the skill. Hope this answer helps! Mark as brainliest! :)

You might be interested in

Need some great assistance! Thanks!

Lostsunrise [7]

Answer:

b

Step-by-step explanation:

step by step explanation I'm probly wrong

7 0

3 years ago

Prove ABC~EDC ?

erastova [34]

Answer:

AA similarity theorem

Step-by-step explanation:

we know that

<u>AA (Angle-Angle) Similarity</u> states that In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar

In this problem we have that

∠BCA=∠ECD ----> by vertical angles

∠BAC=∠DEC ---> because AB is parallel to ED (alternate interior angles)

therefore

Triangles ABC and EDC are similar by AA similarity theorem

8 0

3 years ago

What is the slope of the line that passes through the points (-3, -2) and (5, 6)?

katrin2010 [14]

Answer:

the slope is 54

Step-by-step explanation:

8 0

3 years ago

Carlos tried to shade all the factors of 30 on the hundred chart. Hundred chart with 1, 2, 3, 5, 6, 10, 15, and 30 shaded. What

Nastasia [14]

Answer:

30 is the wrong one because it is not a factor of 100

30 60 90 120

20 40 60 80 100

Step-by-step explanation:

7 0

3 years ago

The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa

horsena [70]

Answer:

7.2 years

Step-by-step explanation:

$f(t) =200(1 - 0.956e^{-0.18t})$

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

$148 =200(1 - 0.956e^{-0.18t})$

divide both sides by 200

$\frac{148}{200} = 1 - 0.956e^{-0.18t}$

Now subtract 1 from both sides

$-0.26= - 0.956e^{-0.18t}$

Divide both sides by -0.956

$\frac{0.26}{0.956} =e^{-0.18t}$

Now take ln on both sides

$\frac{0.26}{0.956} =e^{-0.18t}$

$ln(\frac{0.26}{0.956} )=-0.18tln(e)$

$ln(\frac{0.26}{0.956} )=-0.18t$

divide both sides by -0.18

t=7.2

So 7.2 years

5 0

3 years ago