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aalyn [17]
3 years ago
11

Literal Equations? Anyone? The problems are in the picture! Show solution please! Thanks in advance!

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0
The way to solve is using order of operation PEMDAS. Its very easy. You should be able to solve it yourself. I'll give you the first 3 answers: 
1. g/6=x
2. x=1/2u+1
3. z-m=x
I would give you all the answers but it would be best if you did it yourself. You teacher and parents would be much happier if you learnt the skill. Hope this answer helps! Mark as brainliest! :)
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Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
Anastaziya [24]
The problem is modelled in the first picture shown below

To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector. 

We use the cosine rule to work out the length AB
AB^{2}= 75^{2}+ 150^{2}-(2*75*150*cos(60))
AB^{2} =28125-11250
AB^{2}=16875
AB= \sqrt{16875} =130(nearest whole number)

The third picture shows the full diagram of the vectors

To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B

Angle A
\frac{130}{sin(60)}= \frac{75}{sin(A)}
130sin(A)=75sin(60)
sin(A)= \frac{75sin(60)}{130}
sin(A)=0.4996300406
A= sin^{-1}(0.4996300406)
A=30 (rounded to nearest whole number)

Angle B
B=180-60-30=90

Direction is 60° toward negative x-axis

Answer: Magnitude 130N and direction 60° toward negative x-axis

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