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Jobisdone [24]
2 years ago
9

AB is a straight line. What is the value of y?

Mathematics
1 answer:
Lostsunrise [7]2 years ago
3 0
AB = 180
5y + 3y + 2y + 2y = 180
12y = 180
y = 15

Check the answer by substituting:

5(15) + 3(15) + 2(15) + 2(15)
75 + 45 + 30 + 30 = 180
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pickupchik [31]
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8 0
3 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
3 years ago
In ACDE, the measure of E=90°, the measure of C=70°, and DE = 12 feet.
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

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6 0
2 years ago
What is the area of this trapezoid?<br><br> 26 cm²<br><br> 32 cm²<br><br> 40 cm²<br><br> 72 cm²
KonstantinChe [14]

Answer:

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7 0
2 years ago
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Nostrana [21]

Answer:

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Step-by-step explanation:

Given that,

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The diameter  of the sphere is 3.5 m.

The height of the cylinder is 2 m

Height of the cylinder = Height of bowl− Radius of hemisphere

= 2 - (3.5/2)

= 0.25 m

The volume of the vessel is given by :

V = volume of hemispherical bowl + volume of cylinder

So,

V=\dfrac{2}{3}\pi r^3+\pi r^2 h\\\\V=\dfrac{2}{3}\times \dfrac{22}{7}\times (\dfrac{3.5}{2})^3+\dfrac{22}{7}\times (3.5)^2\times 0.25\\\\V=20.85\ m^3

So, the volume of the vessel is 20.85\ m^3.

5 0
2 years ago
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