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Sindrei [870]
3 years ago
11

If a +2<b+3 then ____.a-b<1a<b+1a<bb<a​

Mathematics
2 answers:
OLga [1]3 years ago
6 0

Answer:

a<b+1

Step-by-step explanation:

a +2<b+3

a<b+3-2

a<b+1

skad [1K]3 years ago
6 0

Answer: a - b < 1 or a < b + 1

a + 2 < b + 3

⇔ a - b < 3 - 2

⇔ a - b < 1

Step-by-step explanation:

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Verify csc^2t-cos t sect= cot^2 t
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Rewriting the left hand side,

csc²t - cost sec t

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= cos²t/sin²t

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2 years ago
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10) Solve the equation for the variable "a":<br> 2(x + a) = 4b
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Answer:

a= 2b-x

Step-by-step explanation:

You have to isolate the variable by dividing each side of the factors that does not contain the variable "a".

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3 years ago
A researcher claims that the average annual salary of part-time community college instructors is at least $45,000. To test this
Doss [256]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The researcher claims :

" the average annual salary of part-time community college instructors is at least $45,000 "

- We will extract the claim made by the researcher to be the Null hypothesis:

                     Null Hypothesis : μ ≥ $45,000

- Any statement otherwise, or point of rejection criteria will denote the Alternate hypothesis that disbands the claim that:

" the average annual salary of part-time community college instructors is less than $45,000 " :

                    Alternate Hypothesis : μ < $45,000

- This type of test with a sample size of n = 25 < 30 and population standard deviation is also not given hints the use t-test statistics and t-critical value reject the claim.

                     Lower tail - one sample - T-test.

6 0
3 years ago
company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26
podryga [215]

Answer:

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

p_v =P(t_{(49)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=25.02 represent the sample mean

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =26 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \geq 26  

Alternative hypothesis:\mu < 26  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one sided test the p value would be:  

p_v =P(t_{(49)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

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The question is asking to choose among the following choices that states the early withdrawal fee of the account given in the problem, base on my calculation and further formulation about the said problem, I would say that the answer would be letter D. $3.75. I hope you are satisfied with my answer 
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3 years ago
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