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yaroslaw [1]
3 years ago
6

Someone please help me with this!!!

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

Ask your teacher AKA me.

Step-by-step explanation:

I'll see you at school tomorrow.

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Can someone please help me with math
allsm [11]

Answer:

the answer is D

Step-by-step explanation:

the graph has a negative correlation

5 0
3 years ago
Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
laiz [17]

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

Solve for y

y = -3x+1

This is in slope intercept form

y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

m* -3 = -1

m = 1/3

The line perpendicular has a slope of 1 / (3) = 1/3

The sum is -3 + 1/3

-9/2 + 1/3 = -8/3

3 0
4 years ago
6th grade math help me plzzzzz
Pepsi [2]

Answer: -1

3 + (-4) = -1

7 0
3 years ago
Please, PLEASE answer this fast! I have 1 hour left before I pass it. Please help :( answer it properly! Thank you in advance.
Inessa05 [86]

Answer:

The range is is set of all second pairs (y-coordinates) while the domain is the set of first pairs(x-coordinates)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the center and radius of the sphere whose equation is given by x2+y2+z2−2x−4y+8z+17=0x2+y2+z2−2x−4y+8z+17=0.
Vedmedyk [2.9K]
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius

we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4

Rewrite as perfect squares

(x+1)²+(y-2²)+(z+4)²=4

(x+1)²+(y-2²)+(z+4)²=2²

the center is the point (-1,2,-4) and the radius is 2 units




4 0
3 years ago
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