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3 years ago

Someone please help me with this!!!

Mathematics

1 answer:

lakkis [162]3 years ago

4 0

Answer:

Ask your teacher AKA me.

Step-by-step explanation:

I'll see you at school tomorrow.

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If there is 1/2 of a pizza and jonas only wants 1/3 of the pizza, how much will he get?

slamgirl [31]

Answer:

Option C is the right answer.

Step-by-step explanation:

1/2 × 1/3 = 1/6

8 0

2 years ago

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Plzzzz help! i will give brainliest 100 points! Let f(x) = 8x3 + 16x2 − 15 and g(x) = 2x + 1. Find f of x over g of x. A. 4 time

Blizzard [7]

Answer:

C. 4 times x squared plus 6 times x minus 3 minus 12 over the quantity 2 times x plus 1

Step-by-step explanation:

f(x) = 8x^3 + 16x^2 − 15

g(x) = 2x + 1.

f(x) / g(x) = (8x^3 + 16x^2 − 15) / (2x + 1)

Using long division

4 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

What is 423 divided by 898?

KiRa [710]

423 divided by 898 is 0.47104677...

Hope I could help! :)

6 0

2 years ago

naomi needs 2 cups of chopped apples for a fruit salad she is making .she only has a 1/4 cup. how many times will naomi need to

Lilit [14]

1/4 × 8 times = 2 cups
ANSWER : 8 times

5 0

3 years ago

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