10.2=10.20
So, 10.2 is bigger than 10.02
Answer:
A prime number has only two factors: 1 and itself. A composite number has more than two factors
Step-by-step explanation:
Can i have a thanks?
Answer:
- $70
- y = 25 + 0.9x
- $250
Step-by-step explanation:
1. 10% of $50 is $5, so the purchases would come to $50 -5 = $45. Added to the $25 membership fee, the total cost for the year would be
$45 +25 = $70
2. The member pays $25 even if no purchases are made. Then any purchases are 100% - 10% = 90% of the marked price. So, the total is ...
y = 25 + 0.90x
3. $25 is 10% of $250, so that is the amount the member would have to purchase to break even on cost.
If you like, you can compare the cost without the membership (x) to the cost with the membership (25+.9x) and see where those costs are equal.
x = 25 +0.9x . . . . . x is the spending level at which there is no advantage
0.1x = 25 . . . . . . . . subtract 0.9x
25/0.1 = x = 250 . . . divide by 0.1
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
#SPJ1
I need a picture of the cylinders to anwser your question.
