Answer:
y=2x+2
Step-by-step explanation:
Given

subject to the constraint

Let

.
The gradient vectors of

and

are:

and

By Lagrange's theorem, there is a number

, such that


It can be seen that

has local extreme values at the given region.
Slope intercept form: y=
−5
7
x+5
The graphing points would be (0,5)(7,0)
Answer:
= 17.7 ( rounded off to one decimal place)
STAY SAFE, GOD BLESS YOU :)
Step-by-step explanation:
851 ÷ 48
= 17.7291
= 17.7 ( rounded off to one decimal place)
Answer:
The answer to the first question is B.
The answer to the second question is C.