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3 years ago

12

Mitchell buys a rug that is 3.8 meters long and 0.9 meters wide. How many square meters does the rug cover? Record your answer b

elow in a complete sentence.

1 answer:

Bond [772]3 years ago

5 0

Answer:3.42

Step-by-step explanation:to get the answer to a area equation you need to multiply the length by the width.

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How can you determine the same price if you are given the regular price and a percent of markdown

OLEGan [10]

You can determine the actual markdown by changing the percentage to a decimal then multiplying it by the price to find your mark down.

4 0

3 years ago

-. Six square-based pyramids fit exactly onto the six faces of a

igor_vitrenko [27]

Answer:

60

Step-by-step explanation:

6 0

3 years ago

A piece of electronic equipment is built with 3 cooling fans. The equipment will function only if at least 2 of the 3 fans are w

PolarNik [594]

Answer:

0.66608

Step-by-step explanation:

Equipment = 3 fans

Mortality = 0.098

We are required to find probability that equipment gets to work for 5years

The question says forces of mortality is constant and also equal to 0.098

To calculate p(x>5)

We will do this by calculating exponentially

e^-0.098x5

= 0.612626394

Probability that at least 2 fans out of 3 are working

3(0.612626394)²+(1-0.612626394)+(0.612626394)³

= 1.1259333x0.3873736+0.2299255

= 0.6660823470

This is approximately

<u>0.6608</u>

this is the probability that the equipment will work for at least 5years

8 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

.98*125<br> 13.75*12<br> 143.43/31

vova2212 [387]

Answer:

n = 6

n, = 6n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2

'

3 0

3 years ago