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balandron [24]
3 years ago
7

How many 4 letter codes can be made and no use the same letter twice

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

The first letter can be any one of the 26 letters in the alphabet.  For each one . . .
The second letter can be any one of the 25 remaining ones.  For each one . . .
The third letter can be any one of the 24 remaining ones.  For each one . . .
The fourth letter can be any one of the 23 remaining ones.

Total possible 4-letter codes = (26 x 25 x 24 x 23) = <em>358,800 </em>


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g(x)=x^2+1\\g(-1)=(-1)^2+1\\g(-1)=1+1\\g(-1)=2

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B) In order to evaluate what g(f(3)) is, let's first investigate what f(3) is using the definition for this function:

f(x)=3x-2\\f(3)=3(3)-2\\f(3)=9-2\\f(3)=7

Now let's find what g(7) is using the definition for this function:

g(x)=x^2+1\\g(7)=(7)^2+1\\g(7)=49+1\\g(7)=50

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