All categories

2 years ago

HELP PLEASE I WILL GIVE BRAINLIEST!!!!

Mathematics

2 answers:

devlian [24]2 years ago

4 0

Answer:

Would you mind posting a picture instead thank you.

miss Akunina [59]2 years ago

3 0

I don’t see the picture

You might be interested in

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

In a scale drawing of Sheikra, a designer

I am Lyosha [343]

Answer:

Doodoo

Step-by-step explanation:

doodoo

7 0

2 years ago

Could anyone help, please?

Dmitry_Shevchenko [17]

First, find the probability of each event:

1) the probability that the spinner will land on a 7.

Since the spinner is split 4 equal sections and there is only 1 sector with 7, we can say the probability of getting a 7 is 1/4 as there is only 1 of 7 out of the total of 4 sections.

<em>and</em>

2) the probability that the spinner will land on B.

Since the spinner is split into 3 equal sections, and there is only 1 sector for B, we can say the probability of getting B is 1/3.

To find the probability of 2 events, we need to multiply the two probabilities.

1/4*1/3 = 1/12

So the answer is 1/12.

4 0

3 years ago

What’s that website I wanna find it

Effectus [21]

What website are you looking for?

6 0

2 years ago

Read 2 more answers

A theater group surveyed 146 audience members after a show and found that 132 of them wanted to see the show again. Find the sta

Sophie [7]

Answer:

0.024

Step-by-step explanation:

Sample size (n) = 146 people

The proportion (p) of people who answered that they would be interested in seeing the show again is:

$p=\frac{132}{146}\\ p=0.9041$

The standard error for a sample of size 'n' and proportion 'p' is:

$SE = \sqrt{\frac{p*(1-p)}{n}}\\SE = \sqrt{\frac{0.9041*(1-0.9041)}{146}}\\ SE=0.024$

The standard error for the sample proportion of audience members who want to see the show again is 0.024.

4 0

2 years ago