The question is Max owes Becky for the movie how much.. the pizza information is a distractor.
Max has a coupon for 1/2 off a third movie ticket when 2 are purchased for regular price of $9.80
2 x (9.80) + 1/2 x (9.80) = 19.60 + 4.90 = $24.50 total all 3 tickets
Since they agree to split the cost equally, divide total cost by 3
24.50 / 3 = $8.16 each
The answer is: Between $8 and $10
Answer:3.294. Hope this helps!
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
So remember that a quarter of a circle is 90 degrees, a half of a circle is 180 degrees, and a whole circle is 360 degrees.
Looking at the image shown, it must be half a circle, whihc is 180 degrees. The image tells us that the 1st angle is 7 degrees. Now, we must find the 2nd angle.
Heres what we know however:
angle 1 + angle 2 = 180 degrees.
How do we know this?
Well, there are only 2 angles in this 180 degrees. We know that the first one is 7 degrees.
Lets input that into our nice lil equation to get an answer:
7 degrees+angle 2 = 180 degrees
Now lets solve.
Subtract 7 on both sides, and your left with:
angle 2 = 173 degrees.
So the answer must be:
<u>173 degrees</u>
Hope this helps! ;)
When solving for a variable, you get the variable you're trying to solve for on one side and everything to the opposite of that variable.
We have the equation <span>5w + 9z = 2z + 3w.
Usually the variable we're solving for we want on the left. But it's fine to have it on the right side, too.
Let's subtract 9z from the left-hand side. That way, the 5w will be alone on the left-hand side.
And remember, anything we do on one side we do to the other side.
</span><span>5w + 9z - 9z = 2z + 3w - 9z
</span><span>5w = -7z + 3w
The 3w term on the right-hand side needs to be removed. So, subtract each side by 3w.
5w - 3w = -7z + 3w - 3w
2w = -7z
Now, we need to divide each side by 2 to see what the w variable is equal to.
2w / 2 = -7z / 2
w = -7z / 2 or w = -3.5z
So, w is equal to -3.5z.
</span>
The given operation involves just swapping the two rows, so carrying out
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
