(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
(15°, 165°)
Step-by-step explanation:
Given the equation 6 sin2(x) = 3, we are to find the value of x that satisfies the equation in the interval [0, 2π]
Given
6 sin2(x) = 3,
Divide both sides by 6
6 sin2(x)/6 = 3/6
sin2(x) = 1/2
2x = sin^-1(0.5)
2x = 30°
x = 30°/2
x = 15°
Since sin is positive in the second quadrant, x2 = 180-15
x = 165°
Hence the values within the interval are 15 and 165.
(15°, 165°)
Answer:C
Step-by-step explanation:
the line above AB signifies that its a line segment
there are points for A and B
Answer:
Step-by-step explanation:
Remember that the range is the set of all y-values. Thus, since the minimum of the function is y=-1, then our range is . In interval notation, we use brackets to show what's included and parentheses to show what's not included.
Answer:
trapazoid
Step-by-step explanation:
