Can someone please help me find the range of this graph?
2 answers:
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Answer:
a) Acceleration = 2.4 m per seconds²
b) Distance traveled = 132 m
Step-by-step explanation:
a). Acceleration of an object is defined by the equation,
v = u + at
Here, v = Final speed
u = Initial speed
a = Acceleration
t = Duration Or time
From the graph attached,
Between t = 0 and t = 5 seconds,
v = 12 meter per second
u = 0
t = 5 seconds
B substituting values in the equation,
12 = 0 + a(5)
a =
a = 2.4 m per seconds²
b). Equation representing distance traveled by an object,
v² = u² + 2as
Here, v = Final speed
u = Initial speed
a = Acceleration
s = Distance traveled
By substituting these values in the given equation,
1). Between t = 0 to t = 5 seconds,
(12)² = 0 + 2(2.4)s
s =
s = 30 m
2). Between t = 5 to t = 12 sec
Car moved with a constant speed (Acceleration = 0)
Distance traveled = Speed × Time
= 12 × 7
= 84 m
3). Acceleration of the car between t = 12 sec to t = 15 sec
By substituting the values in the equation,
v = u - at
0 = 12 - a(3)
a = 4 meter per seconds²
Distance traveled in this duration,
v² = u² - 2as
0 = (12)² - 2(4)s
144 = 8s
s =
s = 18 m
Therefore, total distance covered by the car = 30 + 84 + 18
= 132 meters