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Ymorist [56]
3 years ago
15

Can someone please help me find the range of this graph?

Mathematics
2 answers:
MAXImum [283]3 years ago
7 0
(-5,3) if I can remember how to do this right
PSYCHO15rus [73]3 years ago
5 0
I just did this section in algebra. I’m pretty sure it’s 0 < y < 3
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Factorize 27a³-b³-1-9ab
victus00 [196]

Answer:

Hope this helps!

Please see through the steps below

7 0
3 years ago
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Rachel earned $34 in 4 hours at her job today. She wants to know how much she could earn (e) tomorrow if she works 10 hours at t
Zina [86]
34/4 = 8.5
$8.5 per hour
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8 0
3 years ago
Solve for the vaule of x:-<br> <img src="https://tex.z-dn.net/?f=2x%2B3%20%3D%205" id="TexFormula1" title="2x+3 = 5" alt="2x+3 =
horrorfan [7]

Answer:

The value of x = 1

Step-by-step explanation:

2x+3 = 5

=> 2x = 5-3

=> 2x = 2

=> x = 2/2

=> x = 1

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3 years ago
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Direction: Answer the following problem sets. Please include what is the given, asked, formula, solution and final answer with u
olga2289 [7]

Answer:

7.5s

1.6666 repeating or 1.67 m/s²

Step-by-step explanation:

the equation you have to use is Vfinal=Vstart+acceleration•time

(I'm gonna simplify to Vf=Vs+at)

so you gotta rework it for the two equations

for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at

then divide acceleration on both sides to get t=(Vf–Vs)/a

for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)

so you the plug in

(I don't put the units in to the problem unless needed)

1. t=(Vf–Vs)/a to t=(0–30)/-4.0

t= -30/-4.0

t=7.5 seconds

2. a=(Vf–Vs)/t to a=(10–0)/6.0

a= 10/6.0

a= 1.67m/s²

(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)

8 0
3 years ago
PLEASE HELP I DON'T GET THIS!!!!!!!!!!!!!!!!!!!!!!
Shtirlitz [24]

Answer:

A.

Step-by-step explanation:

Get two points:

(0, 3) and (-6, 0)

Slope = 0.5

y = 0.5x + 3

4 0
4 years ago
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