Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
Well I'm assuming that you want me to simplify the fraction 40/6. Since 40 can go into 6 multiple times, this fraction is going to be a mixed number.
40/6 in simplest form is 6 2/3. Hope I helped!
The sum of the inner angles of a polygon with n sides is 
Since your polygon has 6 sides, the sum of its inner angles has to be
On the other hand, the sum of its inner angles is
And it has to be 720, so we have
C = -840
Isolate C by subtracting 900 on both sides:
C = 60-900
Which then gives u C = -840
.08
.21
.40
is the right answer
