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Mama L [17]
3 years ago
13

Can the sides of a triangle have lengths 1, 1, and 4?

Mathematics
1 answer:
qaws [65]3 years ago
8 0
No, because the hypotenuse needs to be three. It would be true if the lengths were 2, 2, 4
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The Apache Taxi Company charges $2.50 to pick up a passenger and then adds $1.95 per mile. Isaac was charged $27.46 to go from o
nirvana33 [79]
The equation is: 27.46 = 1.95x + 2.50

The answer is 12.8
4 0
3 years ago
Please find the answer and show your work so I can learn thanks!!
irga5000 [103]

Answer:

22.34 {km}^{2}

Step-by-step explanation:

The area of a circle:

A = πr^{2}

The problem gives the diameter of a circle, which is equal to 2*r.

If 5 1/3 = 2*r, then the radius is (16/3)/2 = 8/3.

Plugging this into the area equation,

A = π*{{8/3}}^{2}

A = \frac{{64*π}}{9} or approximately 22.34 {km}^{2}

8 0
3 years ago
Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4​
Triss [41]
<h2>x = 1/4</h2><h2>y = -2</h2><h2>______________</h2>

<h2>Known : </h2>

y = -8x

4x - y = 3

<h2>Asked: </h2>

Use the substitution method to solve the system of equations ?

<h2>Answered:</h2>

<h3>Substitution y</h3>

4x - y = 3

4x - (-8x) = 3

4x + 8x = 3

12x = 3

x = 3/12

x = 1/4

<h3>Substitution x</h3>

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-y = 3 - 1

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y = -2

6 0
3 years ago
Read 2 more answers
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levacccp [35]
I think the answer is D

                                                                    
6 0
3 years ago
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Pamela drove her car 999999 kilometers and used 999 liters of fuel. She wants to know how many kilometers (k) right parenthesis
Sever21 [200]

Answer: Hello, Here you Answer......

132 km

Given that the relationship between kilometers and fuel is proportional, let the distance in km be k and the fuel be f:

thus:

kα cf

k=cf

where k is the constant of proportionality. Thus:

c=k/f

Pamela drove 99 km and used 9 liters;

∴k=99/9=11 km/liter

therefore distance covered is given by:

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hence the distance covered with 12 liters of fuel will be:

k=11×12

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7 0
3 years ago
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