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2 years ago

Help all it says is Rise over Run

Mathematics

1 answer:

jolli1 [7]2 years ago

4 0

Answer:

(3,-4)

Step-by-step explanation:

rise=go up

run=go left or right

if you go left its negitive if you right its positive

always start with the lower dot

hopes this helps id you need more help just message me

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The grid below shows figure Q and its image figure Q' after a transformation:

Masteriza [31]

<h3>Answer: choice B) counterclockwise rotation of 90 degrees around the origin</h3>

To go from figure Q to figure Q', we rotate one of two ways

* 270 degrees clockwise

* 90 degrees counterclockwise

Since "270 clockwise" isn't listed, this means "90 counterclockwise" is the only possibility.

4 0

3 years ago

Simplyify t^12/t^6 *PLEASE HELP*

Julli [10]

Answer:

Step-by-step explanation:

In division when bases are same you do top exponent minus bottom exponent.

So here you do t^(12-6) which is t^6.

3 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

Which equation describes the graph?<br><br> Y=-|x+2|<br> Y=-|x|+2<br> Y=-|x-2|<br> Y=-|x|-2

Lera25 [3.4K]

Answer:

y = -|x|+2

Step-by-step explanation:

The graph represents y = |x| where the given graph opens upside down so it's negative and +2 translation towards the top

Answered by GAUTHMATH

5 0

2 years ago

Please help! Answers only please! Thx!

Butoxors [25]

Answer:

2 cups

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help all it says is Rise over Run​

Help all it says is Rise over Run