3 years ago

Three months ago, Santos could walk 2 miles in 40 minutes. Today he can walk 2 miles in 25 minutes. What is the percent change?

1 answer:

6 0

You just have to subtract the second time he walked from the first time he walked and you will get... 15. So the percent change is 15 minutes.

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Alex17521 [72]

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Step-by-step explanation:

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3 years ago

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Tresset [83]

The answer would be 0.60

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3 years ago

Can anyone please help

shusha [124]

$\text{Hi there! :)}$

$\large\boxed{f'(2) = -\frac{16}{27} }$

$f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2} } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2} }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2} } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}$