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kaheart [24]
3 years ago
5

What is 25 % off $249

Mathematics
2 answers:
Alik [6]3 years ago
7 0
25% of $249 would be (25/100)* 249 = (1/4)*249 = $62.25
zubka84 [21]3 years ago
5 0
p\%=\frac{p}{100}\\\\25\%=\frac{25}{100}=0.25\\\\25\%\ off\ \$249\ is\ 0.25\times\$249=\$62.25
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Solve: -6n + 5 &lt; 11<br> Wich graph shows the solution?
tangare [24]

Answer:

The last graph

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Can anybody find the answers to any of these please
Umnica [9.8K]

(A) SAS

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According to the figure,

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7 0
3 years ago
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
 Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).
Alisiya [41]
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