Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
Answer:
common ratio=0.5, a1= 0.08
Step-by-step explanation:
r=a3/a2
r=a4/a3
compare both we get:
a3/a2=a4/a3
subtitute a2=0.04 and a4=1
a3/0.04=1/a3
(a3)^2=0.04*1
(a3)^2=0.04
taking square root in both sides
a3=0.02
For r, r=a3/a2
subtitute a3 and a2 above
r=0.02/0.04
r=0.5 common ratio
For a1
r=a2/a1
0.5=0.04/a1
a1=0.04/0.5
a1=0.08
Answer:
A
Step-by-step explanation: