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mote1985 [20]
3 years ago
13

Find the GCF: 12,24,36​

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer:

12 is the GCF..........

Lady_Fox [76]3 years ago
6 0

Answer:

12

Step-by-step explanation:

listing the factors

12 : 1, 2, 3, 4, 6, 12

24 : 1, 2, 3, 4, 6, 8, 12, 24

36 : 1, 2, 3, 4, 6, 9, 12, 18, 36

The common factors are 1, 2, 3, 4, 6, 12

The GCF is 12

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What’s the geometric mean of 12 and 5
tino4ka555 [31]

Answer:

The geometric mean is √(60) or about 7.75

Step-by-step explanation:

To find the geometric mean, you have to use the following equation.

GM = √(a×b)

Now we input the two numbers for a and b

GM = √(a×b)

GM = √(12×5)

GM = √(60) or about 7.75

6 0
3 years ago
Roll two fair dice. Each die has six faces. A. Let A be the event that either a 3 or 4 is rolled first followed by an odd number
zhenek [66]

Answer:

A. 0.16

B. 0.58

C. No

D. Dependent

Step-by-step explanation:

A.

The sampling space has 36 outcomes.

The event A has 6 outcomes (3,1), (3,3), (3,5), (4,1), (4,3),(4,5)

So P(A)= 6/36 = 0.16

B.

The table in the picture shows the 15 outcomes that are not allowed, so there are 36-15 = 21 possible outcomes for B and its probability is 21/36 = 0.58

C.

Are A and B mutually exclusive events?

No since their intersection is not empty, for example (3,1) belongs to both A and B

D.

In order for A and B to be independent, it must happen that

P(A∩B)=P(A)P(B)

A∩B={(3,1),(3,3),(4,1)} so P(A∩B) = 3/36  

whereas

P(A)P(B) = (6/36)(21/36) = (1/6)(7/12)=7/72

So A and B are not independent.

7 0
4 years ago
Wall posters are usually sold curled up in cylindrical cardboard tubes. if the length of the tube is 84.5 cm, and the diameter o
LekaFEV [45]
Length of the cylinder = 84.5 cm
Diameter of the cylinder = 2.40 cm

The circumference is
π(2.40 cm) = 2.4π cm.
The area is
A = (2.4π cm)*(84.5 cm) = 637.1 cm²

Answer: a. 637 cm²
8 0
3 years ago
Can someone help please? this is due soon. ill give brainliest
Iteru [2.4K]
Not sure but I think it’s B
4 0
3 years ago
Read 2 more answers
The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
lisabon 2012 [21]

Answer:

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and y_1(x)=e^{2x}

To find the y_2(x) we are applying the following formula,

y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx

           =e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx

           =e^{2x}\int e^{-4x-4x} \ dx

            =e^{2x}\int e^{-8x} \ dx

            =e^{2x}. \frac{e^{-8x}}{-8}

           =-\frac{e^{-6x}}{8}

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

4 0
3 years ago
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